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A thin ring of mass 10 kg is rolling on the horizontal ground such that its center of mass has a velocity of 2 m/s. How much work (in joules) needs to be done to stop it?
- a)40
- b)20
- c)10
- d)80
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
A thin ring of mass 10 kg is rolling on the horizontal ground such tha...
CONCEPT:
Kinetic energy (K.E):
- The energy possessed by a body by virtue of its motion is called kinetic energy.
- The expression for kinetic energy is
Where m = mass of the body and v = velocity of the body
Rotational Kinetic energy (KE):
- The energy, which a body has by virtue of its rotational motion, is called rotational kinetic energy.
- A body rotating about a fixed axis possesses kinetic energy because its constituent particles are in motion, even though the body as a whole remains in place.
- Mathematically rotational kinetic energy can be written as
Where I = moment of inertia and ω = angular velocity.
Condition of rolling is
⇒ V = rω
Where ω = angular velocity and V = linear velocity
CALCULATION:
Given - mass (m) = 10 kg and velocity (V) = 2 m/s
- Moment of inertia of thin circular ring is
⇒ I = mR2
- Work (in joules) needs to be done to stop it is
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A thin ring of mass 10 kg is rolling on the horizontal ground such that its center of mass has a velocity of 2 m/s. How much work (in joules) needs to be done to stop it?a)40b)20c)10d)80Correct answer is option 'A'. Can you explain this answer?
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A thin ring of mass 10 kg is rolling on the horizontal ground such that its center of mass has a velocity of 2 m/s. How much work (in joules) needs to be done to stop it?a)40b)20c)10d)80Correct answer is option 'A'. Can you explain this answer? for EmSAT Achieve 2025 is part of EmSAT Achieve preparation. The Question and answers have been prepared according to the EmSAT Achieve exam syllabus. Information about A thin ring of mass 10 kg is rolling on the horizontal ground such that its center of mass has a velocity of 2 m/s. How much work (in joules) needs to be done to stop it?a)40b)20c)10d)80Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for EmSAT Achieve 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A thin ring of mass 10 kg is rolling on the horizontal ground such that its center of mass has a velocity of 2 m/s. How much work (in joules) needs to be done to stop it?a)40b)20c)10d)80Correct answer is option 'A'. Can you explain this answer?.
A thin ring of mass 10 kg is rolling on the horizontal ground such that its center of mass has a velocity of 2 m/s. How much work (in joules) needs to be done to stop it?a)40b)20c)10d)80Correct answer is option 'A'. Can you explain this answer? for EmSAT Achieve 2025 is part of EmSAT Achieve preparation. The Question and answers have been prepared according to the EmSAT Achieve exam syllabus. Information about A thin ring of mass 10 kg is rolling on the horizontal ground such that its center of mass has a velocity of 2 m/s. How much work (in joules) needs to be done to stop it?a)40b)20c)10d)80Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for EmSAT Achieve 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A thin ring of mass 10 kg is rolling on the horizontal ground such that its center of mass has a velocity of 2 m/s. How much work (in joules) needs to be done to stop it?a)40b)20c)10d)80Correct answer is option 'A'. Can you explain this answer?.
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