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The Q - value of the α - decay of 232Th to the ground state of 228Ra is 4082 keV. The maximum possible kinetic energy of the α - particle is closest to
  • a)
    4082 keV
  • b)
    4050 keV
  • c)
    4035 keV
  • d)
    4012 keV
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
The Q - value of the α - decay of232Th to the ground state of228...

The correct answer is option (4).
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The Q - value of the α - decay of232Th to the ground state of228...
Explanation:
- Q-value Calculation: The Q-value of the α-decay is the difference between the initial mass of the parent nucleus (232Th) and the final mass of the daughter nucleus (228Ra) in atomic mass units (amu), which is then converted to energy in keV.
- Given Q-value = 4082 keV
- Maximum Kinetic Energy: The maximum kinetic energy of the α-particle is equal to the Q-value of the decay process. This is because in the decay, all the Q-value is shared between the α-particle and the daughter nucleus.
- Calculation:
The maximum possible kinetic energy of the α-particle = Q-value = 4082 keV
- Answer: The closest option among the given choices is 4012 keV, which is closest to the actual value of 4082 keV.
Therefore, the correct answer is option 'D' - 4012 keV.
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The Q - value of the α - decay of232Th to the ground state of228Ra is 4082 keV. The maximum possible kinetic energy of theα- particle is closest toa)4082 keVb)4050 keVc)4035 keVd)4012 keVCorrect answer is option 'D'. Can you explain this answer?
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The Q - value of the α - decay of232Th to the ground state of228Ra is 4082 keV. The maximum possible kinetic energy of theα- particle is closest toa)4082 keVb)4050 keVc)4035 keVd)4012 keVCorrect answer is option 'D'. Can you explain this answer? for EmSAT Achieve 2025 is part of EmSAT Achieve preparation. The Question and answers have been prepared according to the EmSAT Achieve exam syllabus. Information about The Q - value of the α - decay of232Th to the ground state of228Ra is 4082 keV. The maximum possible kinetic energy of theα- particle is closest toa)4082 keVb)4050 keVc)4035 keVd)4012 keVCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for EmSAT Achieve 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The Q - value of the α - decay of232Th to the ground state of228Ra is 4082 keV. The maximum possible kinetic energy of theα- particle is closest toa)4082 keVb)4050 keVc)4035 keVd)4012 keVCorrect answer is option 'D'. Can you explain this answer?.
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