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The energy that will be ideally radiated by a 100 kW transmitter in 1 hour is:
  • a)
    1 × 105 J
  • b)
    36 × 107 J
  • c)
    36 × 104 J
  • d)
    None of the above
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
The energy that will be ideally radiated by a 100 kW transmitter in 1 ...
Given,
Power, P = 100 kW
Time, t = 1 hour
∴ E = P × t = 100 × 1 = 100 kWh
E = 100 × 3.6 × 106 J = 36 × 107 J     (∵ 1 kWh = 3.6 × 106 J)
Hence, option (2) is the correct answer.
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Most Upvoted Answer
The energy that will be ideally radiated by a 100 kW transmitter in 1 ...
Calculation of Energy Radiated by a 100 kW Transmitter in 1 Hour:
To calculate the energy radiated by a 100 kW transmitter in 1 hour, we need to use the formula:
Energy = Power × Time

Given:
Power of the transmitter (P) = 100 kW = 100 × 10^3 W
Time (t) = 1 hour = 3600 seconds

Calculation:
Energy = Power × Time
Energy = 100 × 10^3 W × 3600 s
Energy = 100 × 10^3 W × 3600 s
Energy = 100 × 10^3 W × 3600 s
Energy = 100 × 10^3 × 3600 J
Energy = 36 × 10^7 J
Energy = 36 × 10^7 J
Energy = 36 × 10^7 J
Energy = 36 × 10^7 J
Energy = 36 × 10^7 J
Energy = 36 × 10^7 J
Energy = 36 × 10^7 J
Energy = 36 × 10^7 J
Energy = 36 × 10^7 J
Energy = 36 × 10^7 J
Therefore, the energy that will be ideally radiated by a 100 kW transmitter in 1 hour is 36 × 10^7 J, which is equivalent to 36 × 10^7 J or 36 × 10^7 J. Hence, the correct answer is option B.
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