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Uncertainty in the position of an electron moving with a velocity 300 m/s accurate up to 0.001%, will be
  • a)
    1.93 × 10-3 m
  • b)
    1.93 × 10-2 m
  • c)
    3.86 × 10-2 m
  • d)
    3.86 × 10-3 m
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Uncertainty in the position of an electron moving with a velocity 300 ...
v = 300 m/s, Δv = 0.001 % of V;
⇒ Δv = 300 × 0.001 × 10-2 = 3 × 10-3 m/s;
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Most Upvoted Answer
Uncertainty in the position of an electron moving with a velocity 300 ...
Calculating Uncertainty in Position of Electron
- Given: Velocity of electron = 300 m/s, Accuracy = 0.001%

Step 1: Calculate the uncertainty in velocity
- Uncertainty in velocity = 0.001% of 300 m/s
- Uncertainty in velocity = (0.001/100) * 300 = 0.003 m/s

Step 2: Use Heisenberg's Uncertainty Principle
- According to Heisenberg's Uncertainty Principle, Δx * Δp ≥ h/(4π), where h is the reduced Planck's constant.
- Since we are given the velocity, we can find the momentum using the formula p = mv, where m is the mass of the electron.

Step 3: Calculate the uncertainty in position
- Uncertainty in momentum = mass * uncertainty in velocity
- Uncertainty in position = h/(4π * uncertainty in momentum)
Therefore, the uncertainty in the position of the electron moving with a velocity of 300 m/s accurate up to 0.001% is 1.93 × 10^-2 m.
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Uncertainty in the position of an electron moving with a velocity 300 m/s accurate up to 0.001%, will bea)1.93 × 10-3 mb)1.93 × 10-2 mc)3.86 × 10-2 md)3.86 × 10-3 mCorrect answer is option 'B'. Can you explain this answer?
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Uncertainty in the position of an electron moving with a velocity 300 m/s accurate up to 0.001%, will bea)1.93 × 10-3 mb)1.93 × 10-2 mc)3.86 × 10-2 md)3.86 × 10-3 mCorrect answer is option 'B'. Can you explain this answer? for EmSAT Achieve 2025 is part of EmSAT Achieve preparation. The Question and answers have been prepared according to the EmSAT Achieve exam syllabus. Information about Uncertainty in the position of an electron moving with a velocity 300 m/s accurate up to 0.001%, will bea)1.93 × 10-3 mb)1.93 × 10-2 mc)3.86 × 10-2 md)3.86 × 10-3 mCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for EmSAT Achieve 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Uncertainty in the position of an electron moving with a velocity 300 m/s accurate up to 0.001%, will bea)1.93 × 10-3 mb)1.93 × 10-2 mc)3.86 × 10-2 md)3.86 × 10-3 mCorrect answer is option 'B'. Can you explain this answer?.
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