XY and PQ are two parallel chords of a circle on opposite side of the ...
Given, PQ = 10 cm, XY = 24 cm and radius of circle = 13 cm
We need to find the distance between PQ and XY.
Let AB be the diameter of the circle passing through O.
Then, OB = OA = AB/2 = 13 cm
Let M be the midpoint of PQ and N be the midpoint of XY.
Then, OM is perpendicular to PQ and ON is perpendicular to XY.
Also, OM = ON = OB = 13 cm (radii of the same circle).
Now, consider the right-angled triangles OMP and ONX.
We have, OP = OX = PQ/2 = 5 cm and OY = OQ = XY/2 = 12 cm.
Using Pythagoras theorem, we can find
MP and NX as: MP = sqrt(OP^2 - OM^2) = sqrt(5^2 - 13^2) = sqrt(144) = 12 cm NX = sqrt(OX^2 - ON^2) = sqrt(12^2 - 13^2) = sqrt(23) cm
Therefore, the distance between PQ and XY is MN = MP + NX = 12 + sqrt(23) cm Hence, option (A) 17 cm is the correct answer.