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In a simple pendulum experiment the length of pendulum is 90.6 . 10^-2 m the time period is 1.91 second >write the value of acceleration due to gravity to correct significant figure and round it off?
Verified Answer
In a simple pendulum experiment the length of pendulum is 90.6 . 10^-...
Given: length(L) = 90.6 x 10^-2 m
time (T) = 1.91 s
gravity= ?
T= 2pie* under root L/g
therefore g= 4 pie sq. x L/T^2
= 4 x 22 x 90.6 x 10^-2/7 x (1.91)^2
= 312.2094867386937 x 10^-2
by rounding off we get 312.2.x 10^-2 and the remaing signifcant figures are 4.
time (T) = 1.91 s
gravity= ?
T= 2pie* under root L/g
therefore g= 4 pie sq. x L/T^2
= 4 x 22 x 90.6 x 10^-2/7 x (1.91)^2
= 312.2094867386937 x 10^-2
by rounding off we get 312.2.x 10^-2 and the remaing signifcant figures are 4.
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In a simple pendulum experiment the length of pendulum is 90.6 . 10^-...
Introduction
To determine the acceleration due to gravity (g) using a simple pendulum, we can use the formula:
g = 4π²L / T²
where L is the length of the pendulum and T is the time period.
Given Values
- Length of pendulum (L): 90.6 x 10^-2 m
- Time period (T): 1.91 seconds
Calculating g
1. Convert Length:
- L = 90.6 x 10^-2 m = 0.906 m
2. Square the Time Period:
- T² = (1.91)² = 3.6561 seconds²
3. Calculate g:
- g = 4 x π² x (0.906) / (3.6561)
4. Simplify:
- g ≈ 4 x 9.87 x 0.906 / 3.6561
- g ≈ 35.6820 / 3.6561
- g ≈ 9.75 m/s²
Significant Figures
- The length (0.906 m) has 3 significant figures.
- The time period (1.91 s) has 3 significant figures.
When performing calculations, the final result should be reported to the least number of significant figures from the measured values, which is 3 in this case.
Final Result
Thus, the calculated value of acceleration due to gravity g, rounded to 3 significant figures, is:
g ≈ 9.75 m/s²
To determine the acceleration due to gravity (g) using a simple pendulum, we can use the formula:
g = 4π²L / T²
where L is the length of the pendulum and T is the time period.
Given Values
- Length of pendulum (L): 90.6 x 10^-2 m
- Time period (T): 1.91 seconds
Calculating g
1. Convert Length:
- L = 90.6 x 10^-2 m = 0.906 m
2. Square the Time Period:
- T² = (1.91)² = 3.6561 seconds²
3. Calculate g:
- g = 4 x π² x (0.906) / (3.6561)
4. Simplify:
- g ≈ 4 x 9.87 x 0.906 / 3.6561
- g ≈ 35.6820 / 3.6561
- g ≈ 9.75 m/s²
Significant Figures
- The length (0.906 m) has 3 significant figures.
- The time period (1.91 s) has 3 significant figures.
When performing calculations, the final result should be reported to the least number of significant figures from the measured values, which is 3 in this case.
Final Result
Thus, the calculated value of acceleration due to gravity g, rounded to 3 significant figures, is:
g ≈ 9.75 m/s²
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In a simple pendulum experiment the length of pendulum is 90.6 . 10^-2 m the time period is 1.91 second >write the value of acceleration due to gravity to correct significant figure and round it off?
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In a simple pendulum experiment the length of pendulum is 90.6 . 10^-2 m the time period is 1.91 second >write the value of acceleration due to gravity to correct significant figure and round it off? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about In a simple pendulum experiment the length of pendulum is 90.6 . 10^-2 m the time period is 1.91 second >write the value of acceleration due to gravity to correct significant figure and round it off? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a simple pendulum experiment the length of pendulum is 90.6 . 10^-2 m the time period is 1.91 second >write the value of acceleration due to gravity to correct significant figure and round it off?.
In a simple pendulum experiment the length of pendulum is 90.6 . 10^-2 m the time period is 1.91 second >write the value of acceleration due to gravity to correct significant figure and round it off? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about In a simple pendulum experiment the length of pendulum is 90.6 . 10^-2 m the time period is 1.91 second >write the value of acceleration due to gravity to correct significant figure and round it off? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a simple pendulum experiment the length of pendulum is 90.6 . 10^-2 m the time period is 1.91 second >write the value of acceleration due to gravity to correct significant figure and round it off?.
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