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Seeta and Geeta are moving around a circular track with speeds in the ratio of 17:1. They start from a point X on the circular track simultaneously in the same direction. During the time Geeta covers 1 lap, how many times are they diametrically opposite each other?
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Seeta and Geeta are moving around a circular track with speeds in the ...
Analysis:
To find out how many times Seeta and Geeta are diametrically opposite each other during the time Geeta covers 1 lap, we need to consider their relative speeds and the distance between them as they move along the circular track.
Calculating the number of times they are diametrically opposite:
- Seeta and Geeta's speeds are in the ratio of 17:1. This means that Seeta covers 17 units of distance while Geeta covers 1 unit of distance in the same amount of time.
- Since they start from the same point X on the circular track simultaneously and move in the same direction, they will meet at the same point after covering a certain distance.
- The number of times they are diametrically opposite each other is equal to the number of times they meet after covering a complete lap of the track.
- Let the total distance of the circular track be D units. Geeta covers D units while Seeta covers 17D units in the same time frame.
- The relative speed between Seeta and Geeta is 17-1 = 16 units.
- The time taken for them to meet again after starting from the same point X is D/16 units.
- Therefore, the number of times they are diametrically opposite each other during the time Geeta covers 1 lap is 1/(D/16) = 16/D.
This calculation shows that Seeta and Geeta are diametrically opposite each other 16/D times during the time Geeta covers 1 lap on the circular track.
To find out how many times Seeta and Geeta are diametrically opposite each other during the time Geeta covers 1 lap, we need to consider their relative speeds and the distance between them as they move along the circular track.
Calculating the number of times they are diametrically opposite:
- Seeta and Geeta's speeds are in the ratio of 17:1. This means that Seeta covers 17 units of distance while Geeta covers 1 unit of distance in the same amount of time.
- Since they start from the same point X on the circular track simultaneously and move in the same direction, they will meet at the same point after covering a certain distance.
- The number of times they are diametrically opposite each other is equal to the number of times they meet after covering a complete lap of the track.
- Let the total distance of the circular track be D units. Geeta covers D units while Seeta covers 17D units in the same time frame.
- The relative speed between Seeta and Geeta is 17-1 = 16 units.
- The time taken for them to meet again after starting from the same point X is D/16 units.
- Therefore, the number of times they are diametrically opposite each other during the time Geeta covers 1 lap is 1/(D/16) = 16/D.
This calculation shows that Seeta and Geeta are diametrically opposite each other 16/D times during the time Geeta covers 1 lap on the circular track.
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Seeta and Geeta are moving around a circular track with speeds in the ratio of 17:1. They start from a point X on the circular track simultaneously in the same direction. During the time Geeta covers 1 lap, how many times are they diametrically opposite each other?
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