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An unpolarised beam of intensity Io is incident on a polarizer and analyser placed in contact. The angle between the transmission axes of the polarizer and the analyser is θ. What is the intensity of light emerging out of the analyser?
- a)(I0 cos 2θ)/2
- b)I0 cos2θ
- c)I0 cosθ
- d)I0
Correct answer is option 'A'. Can you explain this answer?
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An unpolarised beam of intensity Io is incident on a polarizer and ana...
Suppose the angle between the transmission axes of the analyser and the polarizer is θ. The completely plane polarized light form the polarizer is incident on the analyser. If E0 is the amplitude of the electric vector transmitted by the polarizer, then intensity I0 of the light incident on the analyser is
I ∞ E02
The electric field vector E0 can be resolved into two rectangular components i.e E0 cosθ and E0 sinθ. The analyzer will transmit only the component ( i.e E0 cosθ ) which is parallel to its transmission axis. However, the component E0sinθ will be absorbed by the analyser. Therefore, the intensity I of light transmitted by the analyzer is,
I ∞ ( E0 x cosθ )2
I / I0 = ( E0 x cosθ )2 / E02 = cos2θ
I = I0 x cos2θ
when light passes from polarizer it's intensity becomes half and when passed through analyser it becomes,
I = I0 x cos2θ/2
I ∞ E02
The electric field vector E0 can be resolved into two rectangular components i.e E0 cosθ and E0 sinθ. The analyzer will transmit only the component ( i.e E0 cosθ ) which is parallel to its transmission axis. However, the component E0sinθ will be absorbed by the analyser. Therefore, the intensity I of light transmitted by the analyzer is,
I ∞ ( E0 x cosθ )2
I / I0 = ( E0 x cosθ )2 / E02 = cos2θ
I = I0 x cos2θ
when light passes from polarizer it's intensity becomes half and when passed through analyser it becomes,
I = I0 x cos2θ/2
Most Upvoted Answer
An unpolarised beam of intensity Io is incident on a polarizer and ana...
it's the malus law when light passes from polarizer it's intensity becomes half and when passed through analyzer it becomes the cos^2 of that half.So its answer is a.
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An unpolarised beam of intensity Io is incident on a polarizer and ana...
The angle between the transmission axes of the polarizer and the analyzer is typically denoted as θ.
When an unpolarized beam of intensity Io passes through a polarizer, the transmitted intensity It is given by Malus' law:
It = Io * cos^2(θ)
So, the angle between the transmission axes of the polarizer and the analyzer is crucial in determining the intensity of the transmitted beam.
When an unpolarized beam of intensity Io passes through a polarizer, the transmitted intensity It is given by Malus' law:
It = Io * cos^2(θ)
So, the angle between the transmission axes of the polarizer and the analyzer is crucial in determining the intensity of the transmitted beam.
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An unpolarised beam of intensity Io is incident on a polarizer and analyser placed in contact. The angle between the transmission axes of the polarizer and the analyser is θ. What is the intensity of light emerging out of the analyser?a)(I0cos 2θ)/2b)I0cos2θc)I0cosθd)I0Correct answer is option 'A'. Can you explain this answer?
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