An air bubble inside a glass slab (μ = 1.5) appears at 6 cm when viewed from the opposite side. The thickness of the slab is:a)10 cmb)6.67 cmc)15 cmd)None of the aboveCorrect answer is option 'C'. Can you explain this answer?

Question

An air bubble inside a glass slab (&#956; = 1.5) appears at 6 cm when viewed from the opposite side. The thickness of the slab is:&#8203;a)10 cmb)6.67 cmc)15 cmd)None of the aboveCorrect answer is option 'C'. Can you explain this answer?

Answer

We know that μ=(apparent depth/real depth)

Let the thickness of the slab be t and real depth of the bubble from one side be x. Then

μ=(x/6)=(t−x)/4 or 1.5=x/6 = (t−x)/4

This gives x=9 and 1.5=(t−9)/4 or t=15cm

Answer

Or any transparent material) will undergo refraction as it passes through the material. The amount of refraction that occurs will depend on the angle at which the bubble enters the material, the refractive index of the material, and the size and shape of the bubble.

If the bubble enters the material at a perpendicular (90-degree) angle, it will not undergo any refraction and will continue to travel in a straight line. However, if the bubble enters at an angle, it will be bent or refracted as it passes through the material. The direction of refraction will depend on the angle of incidence and the refractive index of the material.

The size and shape of the bubble can also affect the amount of refraction that occurs. A small bubble may not be affected much by refraction, while a larger bubble may be more noticeably bent or distorted.

Overall, the presence of an air bubble in a glass slab or other transparent material can cause interesting visual effects, such as bending or distortion of light rays passing through the material.

Answer

Mew - apperent depth/real depth
t-x/6 is 1.5
t-x is 9
t = 9+6 =15

Answer

We know that μ=(apparent depth/real depth)

Let the thickness of the slab be t and real depth of the bubble from one side be x. Then

μ=(x/6)=(t−x)/4 or 1.5=x/6 = (t−x)/4

This gives x=9 and 1.5=(t−9)/4 or t=15cm

Answer

We know that μ=(apparent depth/real depth)

Let the thickness of the slab be t and real depth of the bubble from one side be x. Then

μ=(x/6)=(t−x)/4 or 1.5=x/6 = (t−x)/4

This gives x=9 and 1.5=(t−9)/4 or t=15cm

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