The centre and radius of the circle x2+ y2+ 4...
The centre and radius of the circle x2 + y2 + 4x – 6y = 5 is:
• a)
(2, – 3), 2√2
• b)
(– 2, 3), 3√2
• c)
(– 2, 3), 2√2
• d)
(2, – 3), 3√2

### Related Test

 Kushal Hemanth Jun 20, 2018
Related The centre and radius of the circle x2+ y2+ 4x – 6y = 5 is:a)(2, – 3), 2√2b)(– 2, 3), 3√2c)(– 2, 3), 2√2d)(2, – 3), 3√2Correct answer is option 'B'. Can you explain this answer?
Cente=(-g, -f)=(4/-2,6/2) since 2g = 4 and 2f=-6...radius = √g^2+f^2-c =√4+9-5=√8=2√2

 1 Crore+ students have signed up on EduRev. Have you?
 Ciel Knowledge Feb 23, 2022
x2+y2+4x-6y=5
Circle Equation
(x-a)2+(y-b)2=r2 is the circle equation with a radius r, centered at (a,b)
Rewrite x2+y24x-6y=5 in the form of circle standard circle equation
(x-(-2))
2
+(y-3)2=(3
√2)2
Therefore the circle properties are:

(a,b) = (-2,3), r = 3√2

 View courses related to this question Explore JEE courses
 Explore JEE coursesView courses related to this question
 Monpara Om Feb 23, 2020
Related The centre and radius of the circle x2+ y2+ 4x – 6y = 5 is:a)(2, – 3), 2√2b)(– 2, 3), 3√2c)(– 2, 3), 2√2d)(2, – 3), 3√2Correct answer is option 'B'. Can you explain this answer?
X^2+y^2+4x-6y=5
then center =(-4÷2,6÷2)
(-g,-f)=(-2,3)
and
r=√g^2+f^2-c
=√4+9+5
=√18
=3√2
because
x2+y2+2gx+2fy+c=0

 Himanshu Raj Dec 07, 2018
Yes that come from a formula that u must remember to find out the centre and radii..that centre (-g,-f) and radius√g²+f²-c

Question Description
Solutions for The centre and radius of the circle x2+ y2+ 4x – 6y = 5 is:a)(2, – 3), 2√2b)(– 2, 3), 3√2c)(– 2, 3), 2√2d)(2, – 3), 3√2Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.