JEE Question > The centre and radius of the circle x2+ y2+ 4...

The centre and radius of the circle x^{2} + y^{2} + 4x – 6y = 5 is:

- a)(2, – 3), 2√2
- b)(– 2, 3), 3√2
- c)(– 2, 3), 2√2
- d)(2, – 3), 3√2

Correct answer is option 'B'. Can you explain this answer?

Kushal Hemanth
Jun 20, 2018 |

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The centre and radius of the circle x2+ y2+ 4x – 6y = 5 is:a)(2, – 3), 2√2b)(– 2, 3), 3√2c)(– 2, 3), 2√2d)(2, – 3), 3√2Correct answer is option 'B'. Can you explain this answer?

Cente=(-g, -f)=(4/-2,6/2) since 2g = 4 and 2f=-6...radius = √g^2+f^2-c =√4+9-5=√8=2√2

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Ciel Knowledge
Feb 23, 2022 |

x^{2}+y^{2}+4x-6y=5

Circle Equation

(x-a)^{2}+(y-b)^{2}=r^{2 }is the circle equation with a radius r, centered at (a,b)

Rewrite^{ }x^{2}+y^{2}4x-6y=5 in the form of circle standard circle equation

(x-(-2))^{2}^{2Therefore the circle properties are:}

(a,b) = (-2,3), r =^{ }3√2

Circle Equation

(x-a)

Rewrite

(x-(-2))

+(y-3)^{2}=(3

√2)(a,b) = (-2,3), r =

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Monpara Om
Feb 23, 2020 |

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The centre and radius of the circle x2+ y2+ 4x – 6y = 5 is:a)(2, – 3), 2√2b)(– 2, 3), 3√2c)(– 2, 3), 2√2d)(2, – 3), 3√2Correct answer is option 'B'. Can you explain this answer?

X^2+y^2+4x-6y=5

then center =(-4÷2,6÷2)

There will be correct answer:

(-g,-f)=(-2,3)

and

r=√g^2+f^2-c

=√4+9+5

=√18

=3√2

because

x2+y2+2gx+2fy+c=0

then center =(-4÷2,6÷2)

There will be correct answer:

(-g,-f)=(-2,3)

and

r=√g^2+f^2-c

=√4+9+5

=√18

=3√2

because

x2+y2+2gx+2fy+c=0

Himanshu Raj
Dec 07, 2018 |

Yes that come from a formula that u must remember to find out the centre and radii..that centre (-g,-f) and radius√g²+f²-c

Question Description

The centre and radius of the circle x2+ y2+ 4x – 6y = 5 is:a)(2, – 3), 2√2b)(– 2, 3), 3√2c)(– 2, 3), 2√2d)(2, – 3), 3√2Correct answer is option 'B'. Can you explain this answer? for JEE 2022 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The centre and radius of the circle x2+ y2+ 4x – 6y = 5 is:a)(2, – 3), 2√2b)(– 2, 3), 3√2c)(– 2, 3), 2√2d)(2, – 3), 3√2Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2022 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The centre and radius of the circle x2+ y2+ 4x – 6y = 5 is:a)(2, – 3), 2√2b)(– 2, 3), 3√2c)(– 2, 3), 2√2d)(2, – 3), 3√2Correct answer is option 'B'. Can you explain this answer?.

The centre and radius of the circle x2+ y2+ 4x – 6y = 5 is:a)(2, – 3), 2√2b)(– 2, 3), 3√2c)(– 2, 3), 2√2d)(2, – 3), 3√2Correct answer is option 'B'. Can you explain this answer? for JEE 2022 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The centre and radius of the circle x2+ y2+ 4x – 6y = 5 is:a)(2, – 3), 2√2b)(– 2, 3), 3√2c)(– 2, 3), 2√2d)(2, – 3), 3√2Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2022 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The centre and radius of the circle x2+ y2+ 4x – 6y = 5 is:a)(2, – 3), 2√2b)(– 2, 3), 3√2c)(– 2, 3), 2√2d)(2, – 3), 3√2Correct answer is option 'B'. Can you explain this answer?.

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Cente=(-g, -f)=(4/-2,6/2) since 2g = 4 and 2f=-6...radius = √g^2+f^2-c =√4+9-5=√8=2√2