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 The centre and radius of the circle x2 + y2 + 4x – 6y = 5 is:
  • a)
    (2, – 3), 2√2
  • b)
    (– 2, 3), 3√2
  • c)
    (– 2, 3), 2√2
  • d)
    (2, – 3), 3√2
Correct answer is option 'B'. Can you explain this answer?

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Answers

Kushal Hemanth
Jun 20, 2018
Related The centre and radius of the circle x2+ y2+ 4x – 6y = 5 is:a)(2, – 3), 2√2b)(– 2, 3), 3√2c)(– 2, 3), 2√2d)(2, – 3), 3√2Correct answer is option 'B'. Can you explain this answer?
Cente=(-g, -f)=(4/-2,6/2) since 2g = 4 and 2f=-6...radius = √g^2+f^2-c =√4+9-5=√8=2√2

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Ciel Knowledge
Feb 23, 2022
x2+y2+4x-6y=5
Circle Equation
(x-a)2+(y-b)2=r2 is the circle equation with a radius r, centered at (a,b)
Rewrite x2+y24x-6y=5 in the form of circle standard circle equation
(x-(-2))
2
+(y-3)2=(3
√2)2
Therefore the circle properties are:

(a,b) = (-2,3), r = 3√2

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Monpara Om
Feb 23, 2020
Related The centre and radius of the circle x2+ y2+ 4x – 6y = 5 is:a)(2, – 3), 2√2b)(– 2, 3), 3√2c)(– 2, 3), 2√2d)(2, – 3), 3√2Correct answer is option 'B'. Can you explain this answer?
X^2+y^2+4x-6y=5
then center =(-4÷2,6÷2)
There will be correct answer:
(-g,-f)=(-2,3)
and
r=√g^2+f^2-c
=√4+9+5
=√18
=3√2
because
x2+y2+2gx+2fy+c=0

Himanshu Raj
Dec 07, 2018
Yes that come from a formula that u must remember to find out the centre and radii..that centre (-g,-f) and radius√g²+f²-c

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The centre and radius of the circle x2+ y2+ 4x – 6y = 5 is:a)(2, – 3), 2√2b)(– 2, 3), 3√2c)(– 2, 3), 2√2d)(2, – 3), 3√2Correct answer is option 'B'. Can you explain this answer? for JEE 2022 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The centre and radius of the circle x2+ y2+ 4x – 6y = 5 is:a)(2, – 3), 2√2b)(– 2, 3), 3√2c)(– 2, 3), 2√2d)(2, – 3), 3√2Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2022 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The centre and radius of the circle x2+ y2+ 4x – 6y = 5 is:a)(2, – 3), 2√2b)(– 2, 3), 3√2c)(– 2, 3), 2√2d)(2, – 3), 3√2Correct answer is option 'B'. Can you explain this answer?.
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Cente=(-g, -f)=(4/-2,6/2) since 2g = 4 and 2f=-6...radius = √g^2+f^2-c =√4+9-5=√8=2√2