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The centre and radius of the circle x2 + y2 + 4x – 6y = 5 is:
- a)(2, – 3), 2√2
- b)(– 2, 3), 3√2
- c)(– 2, 3), 2√2
- d)(2, – 3), 3√2
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
The centre and radius of the circle x2+ y2+ 4x – 6y = 5 is:a)(2,...
x2+y2+4x-6y=5
Circle Equation
(x-a)2+(y-b)2=r2 is the circle equation with a radius r, centered at (a,b)
Rewrite x2+y24x-6y=5 in the form of circle standard circle equation
(x-(-2))
Therefore the circle properties are:
(a,b) = (-2,3), r = 3√2
Circle Equation
(x-a)2+(y-b)2=r2 is the circle equation with a radius r, centered at (a,b)
Rewrite x2+y24x-6y=5 in the form of circle standard circle equation
(x-(-2))
2
+(y-3)2=(3
√2)2Therefore the circle properties are:
(a,b) = (-2,3), r = 3√2
Most Upvoted Answer
The centre and radius of the circle x2+ y2+ 4x – 6y = 5 is:a)(2,...
Cente=(-g, -f)=(4/-2,6/2) since 2g = 4 and 2f=-6...radius = √g^2+f^2-c =√4+9-5=√8=2√2
Community Answer
The centre and radius of the circle x2+ y2+ 4x – 6y = 5 is:a)(2,...
X^2+y^2+4x-6y=5
then center =(-4÷2,6÷2)
There will be correct answer:
(-g,-f)=(-2,3)
and
r=√g^2+f^2-c
=√4+9+5
=√18
=3√2
because
x2+y2+2gx+2fy+c=0
then center =(-4÷2,6÷2)
There will be correct answer:
(-g,-f)=(-2,3)
and
r=√g^2+f^2-c
=√4+9+5
=√18
=3√2
because
x2+y2+2gx+2fy+c=0
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The centre and radius of the circle x2+ y2+ 4x – 6y = 5 is:a)(2, – 3), 2√2b)(– 2, 3), 3√2c)(– 2, 3), 2√2d)(2, – 3), 3√2Correct answer is option 'B'. Can you explain this answer?
Question Description
The centre and radius of the circle x2+ y2+ 4x – 6y = 5 is:a)(2, – 3), 2√2b)(– 2, 3), 3√2c)(– 2, 3), 2√2d)(2, – 3), 3√2Correct answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The centre and radius of the circle x2+ y2+ 4x – 6y = 5 is:a)(2, – 3), 2√2b)(– 2, 3), 3√2c)(– 2, 3), 2√2d)(2, – 3), 3√2Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The centre and radius of the circle x2+ y2+ 4x – 6y = 5 is:a)(2, – 3), 2√2b)(– 2, 3), 3√2c)(– 2, 3), 2√2d)(2, – 3), 3√2Correct answer is option 'B'. Can you explain this answer?.
The centre and radius of the circle x2+ y2+ 4x – 6y = 5 is:a)(2, – 3), 2√2b)(– 2, 3), 3√2c)(– 2, 3), 2√2d)(2, – 3), 3√2Correct answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The centre and radius of the circle x2+ y2+ 4x – 6y = 5 is:a)(2, – 3), 2√2b)(– 2, 3), 3√2c)(– 2, 3), 2√2d)(2, – 3), 3√2Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The centre and radius of the circle x2+ y2+ 4x – 6y = 5 is:a)(2, – 3), 2√2b)(– 2, 3), 3√2c)(– 2, 3), 2√2d)(2, – 3), 3√2Correct answer is option 'B'. Can you explain this answer?.
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The centre and radius of the circle x2+ y2+ 4x – 6y = 5 is:a)(2, – 3), 2√2b)(– 2, 3), 3√2c)(– 2, 3), 2√2d)(2, – 3), 3√2Correct answer is option 'B'. Can you explain this answer?, a detailed solution for The centre and radius of the circle x2+ y2+ 4x – 6y = 5 is:a)(2, – 3), 2√2b)(– 2, 3), 3√2c)(– 2, 3), 2√2d)(2, – 3), 3√2Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of The centre and radius of the circle x2+ y2+ 4x – 6y = 5 is:a)(2, – 3), 2√2b)(– 2, 3), 3√2c)(– 2, 3), 2√2d)(2, – 3), 3√2Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
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