If the range of x is 2, what would be the range of –3x +50?a)2b)...
Given:
Range of x = 2
To find:
Range of 3x + 50
Solution:
Let's assume the minimum value of x is a and the maximum value of x is b.
So, the range of x = b - a = 2
Now, we need to find the range of 3x + 50.
We know that the range of a linear function ax + b is the same as the range of x, i.e., it is infinite.
But if we add a constant term to the linear function, the range gets shifted by that constant.
In this case, the linear function is 3x and the constant term is 50.
So, the range of 3x + 50 would be the same as the range of 3x, but shifted up by 50 units.
The range of 3x is 3 times the range of x, which is 2.
So, the range of 3x + 50 would be 3 times the range of x, plus 50.
Range of 3x + 50 = 3 * 2 + 50 = 6 + 50 = 56
Therefore, the correct answer is option B) 6.
If the range of x is 2, what would be the range of –3x +50?a)2b)...
I think measure of dispersion is effected by change of scale not change of origin
then i.e.
if -3x + 50
then Y= -3x + 50
Ry = | b |× Rx
|-3|× 2
3×2=6