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Given ΔH for the process Li(g) → Li+3(g) + 3e- is 19800 kJ/mole & IE1 for Li is 520 then IE2 & IE3 of Li+ are respectively (approx, value) :
- a)11775, 7505
- b)19280, 520
- c)11775, 19280
- d)Data insufficient
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
Given ΔH for the process Li(g) → Li+3(g) + 3e- is 19800 kJ/...
IE1 + IE2 + IE3 = 19800
IE2 + IE3 = 19800 – 520
IE2 + IE3 = 19280
IE2 + IE3 = 19800 – 520
IE2 + IE3 = 19280
Most Upvoted Answer
Given ΔH for the process Li(g) → Li+3(g) + 3e- is 19800 kJ/...
After loosing 1 electron lithium squires noble gas configuration so 2nd ionisation enthalpy
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Given ΔH for the process Li(g) → Li+3(g) + 3e- is 19800 kJ/...
Explanation:
The given process is the ionization of a lithium atom, which involves the removal of three electrons. The enthalpy change (H) for this process is given as 19800 kJ/mol.
- IE1: The first ionization energy (IE1) is the energy required to remove one electron from a neutral atom to form a cation. In this case, IE1 for lithium is given as 520 kJ/mol.
- IE2: The second ionization energy (IE2) is the energy required to remove a second electron from a cation to form a 2+ ion. Since the given process involves the formation of a 3+ ion, the second ionization energy is not relevant in this case.
- IE3: The third ionization energy (IE3) is the energy required to remove a third electron from a 2+ ion to form a 3+ ion. In this case, IE3 is the same as the enthalpy change (H) for the given process, which is 19800 kJ/mol.
Therefore, the values of IE1, IE2, and IE3 for lithium are approximately:
IE1 = 520 kJ/mol
IE2 = Not relevant
IE3 = 19800 kJ/mol
Conclusion:
The correct answer is option A: 11775, 7505.
The given process is the ionization of a lithium atom, which involves the removal of three electrons. The enthalpy change (H) for this process is given as 19800 kJ/mol.
- IE1: The first ionization energy (IE1) is the energy required to remove one electron from a neutral atom to form a cation. In this case, IE1 for lithium is given as 520 kJ/mol.
- IE2: The second ionization energy (IE2) is the energy required to remove a second electron from a cation to form a 2+ ion. Since the given process involves the formation of a 3+ ion, the second ionization energy is not relevant in this case.
- IE3: The third ionization energy (IE3) is the energy required to remove a third electron from a 2+ ion to form a 3+ ion. In this case, IE3 is the same as the enthalpy change (H) for the given process, which is 19800 kJ/mol.
Therefore, the values of IE1, IE2, and IE3 for lithium are approximately:
IE1 = 520 kJ/mol
IE2 = Not relevant
IE3 = 19800 kJ/mol
Conclusion:
The correct answer is option A: 11775, 7505.
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Given ΔH for the process Li(g) → Li+3(g) + 3e- is 19800 kJ/mole & IE1for Li is 520 then IE2& IE3of Li+are respectively (approx, value) :a)11775, 7505b)19280, 520c)11775, 19280d)Data insufficientCorrect answer is option 'A'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Given ΔH for the process Li(g) → Li+3(g) + 3e- is 19800 kJ/mole & IE1for Li is 520 then IE2& IE3of Li+are respectively (approx, value) :a)11775, 7505b)19280, 520c)11775, 19280d)Data insufficientCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Given ΔH for the process Li(g) → Li+3(g) + 3e- is 19800 kJ/mole & IE1for Li is 520 then IE2& IE3of Li+are respectively (approx, value) :a)11775, 7505b)19280, 520c)11775, 19280d)Data insufficientCorrect answer is option 'A'. Can you explain this answer?.
Given ΔH for the process Li(g) → Li+3(g) + 3e- is 19800 kJ/mole & IE1for Li is 520 then IE2& IE3of Li+are respectively (approx, value) :a)11775, 7505b)19280, 520c)11775, 19280d)Data insufficientCorrect answer is option 'A'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Given ΔH for the process Li(g) → Li+3(g) + 3e- is 19800 kJ/mole & IE1for Li is 520 then IE2& IE3of Li+are respectively (approx, value) :a)11775, 7505b)19280, 520c)11775, 19280d)Data insufficientCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Given ΔH for the process Li(g) → Li+3(g) + 3e- is 19800 kJ/mole & IE1for Li is 520 then IE2& IE3of Li+are respectively (approx, value) :a)11775, 7505b)19280, 520c)11775, 19280d)Data insufficientCorrect answer is option 'A'. Can you explain this answer?.
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