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A vector of magnitude 14 units, which is parallel to the vector
  • a)
  • b)
  • c)
  • d)
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A vector of magnitude 14 units, which is parallel to the vectora)b)c)d...
Given vector = i + 2j - 3k
Magnitude = √12 + 22 + (-3)2 = √14
Unit vector in direction of resultant = (i + 2j - 3k) / √14
Vector of magnitude 14​ unit in direction of resultant,
⇒ 14[ (i + 2j - 3k) / √14 ]
⇒ √14(i + 2j - 3k)
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Most Upvoted Answer
A vector of magnitude 14 units, which is parallel to the vectora)b)c)d...
Given vector = i + 2j - 3k
Magnitude = √12 + 22 + (-3)2 = √14
Unit vector in direction of resultant = (i + 2j - 3k) / √14
Vector of magnitude 14​ unit in direction of resultant,
⇒ 14[ (i + 2j - 3k) / √14 ]
⇒ √14(i + 2j - 3k)
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Community Answer
A vector of magnitude 14 units, which is parallel to the vectora)b)c)d...
Magnitude of i+2j-3k = (1^2+2^2+3^2)^1/2 therefore 14^1/2 and magnitude is 14 so more 14^1/2 is to be multiplied so as to make its magnotude 14 which is there in option C
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A vector of magnitude 14 units, which is parallel to the vectora)b)c)d)Correct answer is option 'C'. Can you explain this answer?
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