Class 6 Exam > Class 6 Questions > The identity (x+3)(x+4) = x² + 7x + 12 i...
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The identity (x+3)(x+4) = x² + 7x + 12 is true for
- a)two values of x
- b)one value of x
- c)all value of x
- d)None of Above
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
The identity (x+3)(x+4) = x² + 7x + 12 is true fora)two values of...
L. H. S. =(X +3)(X +4) = ( X ^2 +4X + 3X + 12) = X^2 + 7X + 12 = R. H. S. L. H. S =R. H. S. here u can take any value of X it will same that L. h. s = R. h. s.
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Community Answer
The identity (x+3)(x+4) = x² + 7x + 12 is true fora)two values of...
The given equation is (x^3)(x^4) = x.
To simplify this equation, we can use the properties of exponents. When we multiply two numbers with the same base, we add their exponents. Therefore, (x^3)(x^4) can be simplified as x^(3+4) = x^7.
So, the equation becomes x^7 = x.
Now, to solve for x, we can rewrite the equation as x^7 - x = 0.
Factoring out x, we get x(x^6 - 1) = 0.
Setting each factor equal to zero, we have x = 0 and x^6 - 1 = 0.
Solving x^6 - 1 = 0, we can add 1 to both sides to get x^6 = 1.
Taking the sixth root of both sides, we have x = 1.
Therefore, the solution to the equation (x^3)(x^4) = x is x = 0 and x = 1.
To simplify this equation, we can use the properties of exponents. When we multiply two numbers with the same base, we add their exponents. Therefore, (x^3)(x^4) can be simplified as x^(3+4) = x^7.
So, the equation becomes x^7 = x.
Now, to solve for x, we can rewrite the equation as x^7 - x = 0.
Factoring out x, we get x(x^6 - 1) = 0.
Setting each factor equal to zero, we have x = 0 and x^6 - 1 = 0.
Solving x^6 - 1 = 0, we can add 1 to both sides to get x^6 = 1.
Taking the sixth root of both sides, we have x = 1.
Therefore, the solution to the equation (x^3)(x^4) = x is x = 0 and x = 1.
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The identity (x+3)(x+4) = x² + 7x + 12 is true fora)two values of xb)one value of xc)all value of xd)None of AboveCorrect answer is option 'C'. Can you explain this answer? for Class 6 2025 is part of Class 6 preparation. The Question and answers have been prepared according to the Class 6 exam syllabus. Information about The identity (x+3)(x+4) = x² + 7x + 12 is true fora)two values of xb)one value of xc)all value of xd)None of AboveCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 6 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The identity (x+3)(x+4) = x² + 7x + 12 is true fora)two values of xb)one value of xc)all value of xd)None of AboveCorrect answer is option 'C'. Can you explain this answer?.
The identity (x+3)(x+4) = x² + 7x + 12 is true fora)two values of xb)one value of xc)all value of xd)None of AboveCorrect answer is option 'C'. Can you explain this answer? for Class 6 2025 is part of Class 6 preparation. The Question and answers have been prepared according to the Class 6 exam syllabus. Information about The identity (x+3)(x+4) = x² + 7x + 12 is true fora)two values of xb)one value of xc)all value of xd)None of AboveCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 6 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The identity (x+3)(x+4) = x² + 7x + 12 is true fora)two values of xb)one value of xc)all value of xd)None of AboveCorrect answer is option 'C'. Can you explain this answer?.
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