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The total number of three-digit numbers, with one digit repeated exactly two times, is ______. (in integers)
Correct answer is '243'. Can you explain this answer?
Most Upvoted Answer
The total number of three-digit numbers, with one digit repeated exact...
If 0 is taken twice, then number of ways = 9
If 0 is taken once, then 9C1 × 2 = 18
If 0 is not taken, then 9C1 8C1.3 = 216
Total = 243
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Community Answer
The total number of three-digit numbers, with one digit repeated exact...
Explanation:

Total three-digit numbers:
- There are 900 three-digit numbers (100 to 999).

Numbers with all distinct digits:
- There are 9 choices for the hundreds place (1 to 9), 9 choices for the tens place (excluding the digit in the hundreds place), and 8 choices for the units place (excluding the digits in the hundreds and tens places).
- So, the total number of three-digit numbers with all distinct digits is 9 x 9 x 8 = 648.

Numbers with one digit repeated exactly two times:
- There are 9 choices for the repeated digit and 3 choices for the position of the non-repeated digit.
- So, the total number of three-digit numbers with one digit repeated exactly two times is 9 x 3 = 27.

Total number of three-digit numbers with one digit repeated exactly two times:
- Adding these two cases, we get 648 (distinct digits) + 27 (one digit repeated) = 675.
- However, we need to exclude the numbers with all digits being the same (111, 222, ..., 999).
- There are 9 such numbers.
- Therefore, the total number of three-digit numbers with one digit repeated exactly two times is 675 - 9 = 666.

Final Answer:
- The total number of three-digit numbers, with one digit repeated exactly two times, is 666.
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The total number of three-digit numbers, with one digit repeated exactly two times, is ______. (in integers)Correct answer is '243'. Can you explain this answer?
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