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Let p be the probablity function on S={X1,X2,X3} if p(X3)=1/3 and p(x1)is 1/4 then p(x2) is equal to?
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Let p be the probablity function on S={X1,X2,X3} if p(X3)=1/3 and p(x1...
1. **Given Probabilities**
Given that p(X3) = 1/3 and p(X1) = 1/4, we need to find the probability p(X2) for the function p on the set S={X1, X2, X3}.
2. **Total Probability**
The sum of probabilities for all elements in a set must equal 1. Therefore, we have:
p(X1) + p(X2) + p(X3) = 1
3. **Using Given Probabilities**
Substitute the given probabilities into the equation:
1/4 + p(X2) + 1/3 = 1
4. **Solving for p(X2)**
To find p(X2), we first simplify the equation:
p(X2) = 1 - 1/4 - 1/3
p(X2) = 12/12 - 3/12 - 4/12
p(X2) = 5/12
5. **Conclusion**
Therefore, the probability p(X2) for the function p on the set S={X1, X2, X3} is 5/12. This completes the calculation based on the given probabilities for X1 and X3.
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Let p be the probablity function on S={X1,X2,X3} if p(X3)=1/3 and p(x1)is 1/4 then p(x2) is equal to?
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Let p be the probablity function on S={X1,X2,X3} if p(X3)=1/3 and p(x1)is 1/4 then p(x2) is equal to? for CA Foundation 2024 is part of CA Foundation preparation. The Question and answers have been prepared according to the CA Foundation exam syllabus. Information about Let p be the probablity function on S={X1,X2,X3} if p(X3)=1/3 and p(x1)is 1/4 then p(x2) is equal to? covers all topics & solutions for CA Foundation 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Let p be the probablity function on S={X1,X2,X3} if p(X3)=1/3 and p(x1)is 1/4 then p(x2) is equal to?.
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