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Light with an energy flux of 500 kW/m2 falls for 5 minutes at normal incidence on a non-reflecting circular surface with a radius of 10 cm. The total momentum delivered to this surface has a magnitude of ______.
  • a)
    5π × 10-3 kg m s-1
  • b)
    7.5 π × 10-3 kg m s-1
  • c)
    25 π × 10-3 kg m s-1​
  • d)
    8.3 π × 10-3 kg m s-1​
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
Light with an energy flux of 500 kW/m2falls for 5 minutes at normal in...
Given data:
- Energy flux of light = 500 kW/m2
- Time of light exposure = 5 minutes
- Radius of the circular surface = 10 cm

Calculations:
1. Convert the radius to meters: 10 cm = 0.1 m
2. Calculate the area of the circular surface:
Area = πr^2 = π(0.1)^2 = 0.0314 m2
3. Calculate the energy received by the surface:
Energy = Energy flux × Area × Time
= 500 × 10^3 × 0.0314 × 5 × 60
= 471 kJ
4. The momentum delivered to the surface can be calculated using the formula:
Momentum = Energy / speed of light
= 471 × 10^3 / 3 × 10^8
= 1.57 × 10^-3 kg m s^-1

Final Answer:
The total momentum delivered to the surface has a magnitude of 1.57 × 10^-3 kg m s^-1, which is approximately 5π × 10^-3 kg m s^-1. Therefore, the correct answer is option 'A' (5π × 10^-3 kg m s^-1).
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Light with an energy flux of 500 kW/m2falls for 5 minutes at normal incidence on a non-reflecting circular surface with a radius of 10 cm. The total momentum delivered to this surface has a magnitude of ______.a)5π× 10-3kg m s-1b)7.5 π× 10-3kg m s-1c)25 π × 10-3 kg m s-1d)8.3 π × 10-3 kg m s-1Correct answer is option 'A'. Can you explain this answer?
Question Description
Light with an energy flux of 500 kW/m2falls for 5 minutes at normal incidence on a non-reflecting circular surface with a radius of 10 cm. The total momentum delivered to this surface has a magnitude of ______.a)5π× 10-3kg m s-1b)7.5 π× 10-3kg m s-1c)25 π × 10-3 kg m s-1d)8.3 π × 10-3 kg m s-1Correct answer is option 'A'. Can you explain this answer? for EmSAT Achieve 2025 is part of EmSAT Achieve preparation. The Question and answers have been prepared according to the EmSAT Achieve exam syllabus. Information about Light with an energy flux of 500 kW/m2falls for 5 minutes at normal incidence on a non-reflecting circular surface with a radius of 10 cm. The total momentum delivered to this surface has a magnitude of ______.a)5π× 10-3kg m s-1b)7.5 π× 10-3kg m s-1c)25 π × 10-3 kg m s-1d)8.3 π × 10-3 kg m s-1Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for EmSAT Achieve 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Light with an energy flux of 500 kW/m2falls for 5 minutes at normal incidence on a non-reflecting circular surface with a radius of 10 cm. The total momentum delivered to this surface has a magnitude of ______.a)5π× 10-3kg m s-1b)7.5 π× 10-3kg m s-1c)25 π × 10-3 kg m s-1d)8.3 π × 10-3 kg m s-1Correct answer is option 'A'. Can you explain this answer?.
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