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The function f is defined as follows:
int f (int n) {
if (n <= 1) return 1;
else if (n % 2 == 0) return f(n/2);
else return f(3n - 1);
}
Assuming that arbitrarily large integers can be passed as a parameter to the function, consider the following statements.
i. The function f terminates for finitely many different values of n ≥ 1.
ii. The function f terminates for infinitely many different values of n ≥ 1.
iii. The function f does not terminate for finitely many different values of n ≥ 1.
iv. The function f does not terminate for infinitely many different values of n ≥ 1.
Which one of the following options is true of the above?
A. i and iii
B. i and iv
C. ii and iii
D. ii and iv
  • a)
    A
  • b)
    B
  • c)
    C
  • d)
    D
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
The function f is defined as follows:int f (int n) {if (n <= 1) re...
The function terminates for all powers of 2 (which is infinite), hence (i) is false and (ii) is TRUE.
Let n = 5.
Now, recursive calls will go like 5 - 14 - 7 - 20 - 10 - 5 -
And this goes into infinite recursion. And if we multiply 5 with any power of 2, also result will be infinite recursion. Since, there are infinite powers of 2 possible, there are infinite recursions possible (even considering this case only). So, (iv) is TRUE and (iii) is false.
So, correct answer is (D)
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Most Upvoted Answer
The function f is defined as follows:int f (int n) {if (n <= 1) re...
The given function f is a recursive function that takes an integer n as input and performs certain operations based on the value of n. Let's analyze the function to understand its behavior.

Termination of the function:
- The function terminates when the input value n becomes equal to 1 (n = 1).
- This is because when n = 1, the first condition in the if statement is satisfied and the function returns 1.

Recursive calls:
- If the input value n is not equal to 1, the function performs further operations.
- If n is even (n % 2 == 0), the function makes a recursive call with n/2 as the input.
- If n is odd (n % 2 != 0), the function makes a recursive call with 3n - 1 as the input.

Based on the above analysis, let's evaluate the given statements:

i. The function f terminates for finitely many different values of n > 1.
- This statement is true because for any value of n that eventually becomes 1, the function terminates. However, there are infinitely many values of n for which the function does not terminate.

ii. The function f terminates for infinitely many different values of n > 1.
- This statement is false because the function terminates only when n becomes 1. It does not terminate for infinitely many values of n.

iii. The function f does not terminate for finitely many different values of n > 1.
- This statement is true because for any value of n that is not equal to 1 and does not eventually become 1, the function does not terminate. There are infinitely many values of n for which the function does not terminate.

iv. The function f does not terminate for infinitely many different values of n > 1.
- This statement is true because there are infinitely many values of n for which the function does not terminate. This is because if n is not equal to 1 and not eventually becomes 1, the function keeps making recursive calls indefinitely.

Therefore, the correct option is D. ii and iv.
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The function f is defined as follows:int f (int n) {if (n <= 1) return 1;else if (n % 2 == 0) return f(n/2);else return f(3n - 1);}Assuming that arbitrarily large integers can be passed as a parameter to the function, consider the following statements.i. The function f terminates for finitely many different values of n ≥ 1.ii. The function f terminates for infinitely many different values of n ≥ 1.iii. The function f does not terminate for finitely many different values of n ≥ 1.iv. The function f does not terminate for infinitely many different values of n ≥ 1.Which one of the following options is true of the above?A. i and iiiB. i and ivC. ii and iiiD. ii and iva)Ab)Bc)Cd)DCorrect answer is option 'D'. Can you explain this answer?
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The function f is defined as follows:int f (int n) {if (n <= 1) return 1;else if (n % 2 == 0) return f(n/2);else return f(3n - 1);}Assuming that arbitrarily large integers can be passed as a parameter to the function, consider the following statements.i. The function f terminates for finitely many different values of n ≥ 1.ii. The function f terminates for infinitely many different values of n ≥ 1.iii. The function f does not terminate for finitely many different values of n ≥ 1.iv. The function f does not terminate for infinitely many different values of n ≥ 1.Which one of the following options is true of the above?A. i and iiiB. i and ivC. ii and iiiD. ii and iva)Ab)Bc)Cd)DCorrect answer is option 'D'. Can you explain this answer? for Computer Science Engineering (CSE) 2024 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about The function f is defined as follows:int f (int n) {if (n <= 1) return 1;else if (n % 2 == 0) return f(n/2);else return f(3n - 1);}Assuming that arbitrarily large integers can be passed as a parameter to the function, consider the following statements.i. The function f terminates for finitely many different values of n ≥ 1.ii. The function f terminates for infinitely many different values of n ≥ 1.iii. The function f does not terminate for finitely many different values of n ≥ 1.iv. The function f does not terminate for infinitely many different values of n ≥ 1.Which one of the following options is true of the above?A. i and iiiB. i and ivC. ii and iiiD. ii and iva)Ab)Bc)Cd)DCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The function f is defined as follows:int f (int n) {if (n <= 1) return 1;else if (n % 2 == 0) return f(n/2);else return f(3n - 1);}Assuming that arbitrarily large integers can be passed as a parameter to the function, consider the following statements.i. The function f terminates for finitely many different values of n ≥ 1.ii. The function f terminates for infinitely many different values of n ≥ 1.iii. The function f does not terminate for finitely many different values of n ≥ 1.iv. The function f does not terminate for infinitely many different values of n ≥ 1.Which one of the following options is true of the above?A. i and iiiB. i and ivC. ii and iiiD. ii and iva)Ab)Bc)Cd)DCorrect answer is option 'D'. Can you explain this answer?.
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