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Question 33:
If a bus travelling at 20 m/s is subjected to a steady deceleration of 5 m/s2, how long will it take to come to rest ?
If a bus travelling at 20 m/s is subjected to a steady deceleration of 5 m/s2, how long will it take to come to rest ?
Most Upvoted Answer
Question 33:If a bus travelling at 20 m/s is subjected to a steady dec...
Calculating the time taken for the bus to come to rest:
The first step in solving this problem is to determine the time it will take for the bus to come to rest under the given conditions.
Given:
- Initial velocity (u) = 20 m/s
- Deceleration (a) = -5 m/s^2 (negative because it is deceleration)
- Final velocity (v) = 0 m/s (since the bus comes to rest)
Using the equation of motion:
v = u + at
0 = 20 - 5t
5t = 20
t = 20 / 5
t = 4 seconds
Therefore, it will take the bus 4 seconds to come to rest under the given conditions.
Explanation:
- The initial velocity of the bus is 20 m/s and it is subjected to a deceleration of 5 m/s^2. This means that every second, the velocity of the bus decreases by 5 m/s.
- Using the equation of motion, we can calculate the time it will take for the bus to come to rest by setting the final velocity to 0 and solving for time.
- In this case, the bus will take 4 seconds to come to rest after applying the brakes. During this time, the velocity of the bus will decrease from 20 m/s to 0 m/s at a steady rate of 5 m/s^2.
- It is important to note that the negative sign in the deceleration indicates that the acceleration is in the opposite direction of the initial velocity, causing the bus to slow down.
The first step in solving this problem is to determine the time it will take for the bus to come to rest under the given conditions.
Given:
- Initial velocity (u) = 20 m/s
- Deceleration (a) = -5 m/s^2 (negative because it is deceleration)
- Final velocity (v) = 0 m/s (since the bus comes to rest)
Using the equation of motion:
v = u + at
0 = 20 - 5t
5t = 20
t = 20 / 5
t = 4 seconds
Therefore, it will take the bus 4 seconds to come to rest under the given conditions.
Explanation:
- The initial velocity of the bus is 20 m/s and it is subjected to a deceleration of 5 m/s^2. This means that every second, the velocity of the bus decreases by 5 m/s.
- Using the equation of motion, we can calculate the time it will take for the bus to come to rest by setting the final velocity to 0 and solving for time.
- In this case, the bus will take 4 seconds to come to rest after applying the brakes. During this time, the velocity of the bus will decrease from 20 m/s to 0 m/s at a steady rate of 5 m/s^2.
- It is important to note that the negative sign in the deceleration indicates that the acceleration is in the opposite direction of the initial velocity, causing the bus to slow down.
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Question 33:If a bus travelling at 20 m/s is subjected to a steady deceleration of 5 m/s2, how long will it take to come to rest ?
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Question 33:If a bus travelling at 20 m/s is subjected to a steady deceleration of 5 m/s2, how long will it take to come to rest ? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about Question 33:If a bus travelling at 20 m/s is subjected to a steady deceleration of 5 m/s2, how long will it take to come to rest ? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Question 33:If a bus travelling at 20 m/s is subjected to a steady deceleration of 5 m/s2, how long will it take to come to rest ?.
Question 33:If a bus travelling at 20 m/s is subjected to a steady deceleration of 5 m/s2, how long will it take to come to rest ? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about Question 33:If a bus travelling at 20 m/s is subjected to a steady deceleration of 5 m/s2, how long will it take to come to rest ? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Question 33:If a bus travelling at 20 m/s is subjected to a steady deceleration of 5 m/s2, how long will it take to come to rest ?.
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