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The volume of oxygen produced from 3l of chlorine according to the following equations (unbalanced) at STP is Cl2+NaOH-- NaCl+NaClO3+H2O NaClO3--NaCl+O2?
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The volume of oxygen produced from 3l of chlorine according to the fol...
- Given Equations:
- Equation 1: Cl2 + NaOH → NaCl + NaClO3 + H2O
- Equation 2: NaClO3 → NaCl + O2
- Volume of Oxygen Produced:
- First, we need to balance the equations to determine the stoichiometry of the reaction.
- Once the equations are balanced, we can see that 1 mole of Cl2 produces 1 mole of NaClO3 and 1 mole of NaClO3 decomposes to produce 1 mole of O2.
- Given 3 liters of Cl2 at STP, we can calculate the moles of Cl2 using the ideal gas law.
- Then, using the stoichiometry of the balanced equations, we can determine the moles of O2 produced.
- Finally, we can convert the moles of O2 to volume using the ideal gas law at STP (1 mole of gas = 22.4 L at STP).
- Conclusion:
- By following the steps outlined above, we can calculate the volume of oxygen produced from 3 liters of chlorine according to the given equations at STP.
- Equation 1: Cl2 + NaOH → NaCl + NaClO3 + H2O
- Equation 2: NaClO3 → NaCl + O2
- Volume of Oxygen Produced:
- First, we need to balance the equations to determine the stoichiometry of the reaction.
- Once the equations are balanced, we can see that 1 mole of Cl2 produces 1 mole of NaClO3 and 1 mole of NaClO3 decomposes to produce 1 mole of O2.
- Given 3 liters of Cl2 at STP, we can calculate the moles of Cl2 using the ideal gas law.
- Then, using the stoichiometry of the balanced equations, we can determine the moles of O2 produced.
- Finally, we can convert the moles of O2 to volume using the ideal gas law at STP (1 mole of gas = 22.4 L at STP).
- Conclusion:
- By following the steps outlined above, we can calculate the volume of oxygen produced from 3 liters of chlorine according to the given equations at STP.
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The volume of oxygen produced from 3l of chlorine according to the following equations (unbalanced) at STP is Cl2+NaOH-- NaCl+NaClO3+H2O NaClO3--NaCl+O2?
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The volume of oxygen produced from 3l of chlorine according to the following equations (unbalanced) at STP is Cl2+NaOH-- NaCl+NaClO3+H2O NaClO3--NaCl+O2? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about The volume of oxygen produced from 3l of chlorine according to the following equations (unbalanced) at STP is Cl2+NaOH-- NaCl+NaClO3+H2O NaClO3--NaCl+O2? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The volume of oxygen produced from 3l of chlorine according to the following equations (unbalanced) at STP is Cl2+NaOH-- NaCl+NaClO3+H2O NaClO3--NaCl+O2?.
The volume of oxygen produced from 3l of chlorine according to the following equations (unbalanced) at STP is Cl2+NaOH-- NaCl+NaClO3+H2O NaClO3--NaCl+O2? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about The volume of oxygen produced from 3l of chlorine according to the following equations (unbalanced) at STP is Cl2+NaOH-- NaCl+NaClO3+H2O NaClO3--NaCl+O2? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The volume of oxygen produced from 3l of chlorine according to the following equations (unbalanced) at STP is Cl2+NaOH-- NaCl+NaClO3+H2O NaClO3--NaCl+O2?.
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