Consider the unimolecular reaction: A(g) → products, were made:(I...
Explanation:
The given unimolecular reaction is A(g) → products.
Order of reaction: The order of the reaction is the power to which the concentration of the reactant is raised in the rate law equation.
Rate law equation: The rate law equation for the given unimolecular reaction is Rate = k[A], where k is the rate constant and [A] is the concentration of the reactant A.
(a) I and II are incorrect.
(I) The reaction is second order at low pressure and becomes first order at high pressure.
If the reaction is second order, then the rate law equation should be Rate = k[A]^2. However, the given rate law equation is Rate = k[A]. Therefore, option I is incorrect.
(II) The reaction is first order at low pressure and becomes second order at high pressure.
If the reaction is first order, then the rate law equation should be Rate = k[A]. However, the given information states that the reaction becomes second order at high pressure. Therefore, option II is also incorrect.
(b) II and III are incorrect.
(II) and (III) contradict each other. If the reaction is both first order and zero order, it is impossible. Therefore, option II and III are incorrect.
(c) Only III is incorrect.
(III) The reaction is zero order.
If the reaction is zero order, then the rate law equation should be Rate = k[A]^0 = k. This means that the rate of the reaction is independent of the concentration of the reactant A. Therefore, option III is correct.
Explanation in short:
- The given unimolecular reaction is A(g) → products.
- Order of reaction is the power to which the concentration of the reactant is raised in the rate law equation.
- Rate law equation for the given unimolecular reaction is Rate = k[A], where k is the rate constant and [A] is the concentration of the reactant A.
- Option I and II are incorrect.
- Option III is correct.
- If the reaction is zero order, then the rate law equation should be Rate = k[A]^0 = k.
Consider the unimolecular reaction: A(g) → products, were made:(I...
According to Lindemann mechanism,
at low concentration it will be second order and at high concentration it will be 1st order.