24√3x^3-125y^3 factorise it? plz it is important?
24 *3^(1/2)^x^3 - 125 y^3
= 8* 3* 3^1/2 * x^3 - (5*y)^3
= (8*3^1/2*x)^3 - (5*y)^3
= (8*3^1/2*x - 5*y)(192x^2 + 40*3^1/2*x*y + 25*y^2)
As (a3 -b3)= (a-b)(a2+ab+b2)
24√3x^3-125y^3 factorise it? plz it is important?
Factorising 24√3x^3-125y^3
To factorise the given expression, we can use the difference of cubes formula. The difference of cubes formula states that for any two numbers a and b, the expression a^3 - b^3 can be factorised as (a - b)(a^2 + ab + b^2).
In our case, we have 24√3x^3 - 125y^3, which can be rewritten as (2^3 * 3 * x^3) - (5^3 * y^3). Let's apply the difference of cubes formula to factorise it.
Step 1: Identify the cubes
The cubes in our expression are (2x)^3 and (5y)^3.
Step 2: Apply the difference of cubes formula
Using the difference of cubes formula, we can rewrite our expression as follows:
24√3x^3 - 125y^3 = (2x)^3 - (5y)^3
This can now be factorised as:
= [(2x) - (5y)][(2x)^2 + (2x)(5y) + (5y)^2]
Step 3: Simplify the factors
Now, let's simplify the factors:
= (2x - 5y)(4x^2 + 10xy + 25y^2)
Therefore, the factorised form of 24√3x^3 - 125y^3 is (2x - 5y)(4x^2 + 10xy + 25y^2).
Summary:
To factorise the expression 24√3x^3 - 125y^3, we used the difference of cubes formula. By identifying the cubes and applying the formula, we obtained the factorised form as (2x - 5y)(4x^2 + 10xy + 25y^2).