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The equivalent emf of two cells (with ε1 > ε2) in series if we connect two negative electrodes of adjacent cells is
  • a)
    εequivalent = 
  • b)
    εequivalent = 
  • c)
    εequivalent = ε2 - ε1 (ε1 > ε2)
  • d)
    εequivalent = ε1 - ε2 (ε1 > ε2)
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
The equivalent emf of two cells (with ε1> ε2) in series ...
When we connect cells to form a battery, we join opposite ends(+ve with -ve and vice versa) to get supporting emf, i.e. net emf get added, but when we join the same polarities(-ve with -ve, like in the question), they oppose each other, hence net emf is the difference b/w them.
The expression for equivalent emf when two cells of emf’s
εeq = ε1 - ε2 (ε1> ε2)
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The equivalent emf of two cells (with ε1> ε2) in series ...
When we connect cells to form a battery, we join opposite ends(+ve with -ve and vice versa) to get supporting emf, i.e. net emf get added, but when we join the same polarities(-ve with -ve, like in the question), they oppose each other, hence net emf is the difference b/w them.
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The equivalent emf of two cells (with ε1> ε2) in series ...
When we connect cells to form a battery, we join opposite ends(+ve with -ve and vice versa) to get supporting emf, i.e. net emf get added, but when we join the same polarities(-ve with -ve, like in the question), they oppose each other, hence net emf is the difference b/w them.
The expression for equivalent emf when two cells of emf’s
εeq = ε1 - ε2 (ε1> ε2)
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Read the following text and answer the following questions on the basis of the same: Tribo-electric series: The tribo-electric series is a list that ranks materials according to their tendency to gain or lose electrons. The process of electron transfer as a result of two objects coming into contact with one another and then separating is called tribo-electric charging. During such an interaction, one of the two objects will always gain electrons (becoming negatively charge d) and the other object will lose electrons (becoming positively charged). The relative position of the two objects on the tribo-electric series will define which object gains electrons and which object loses electrons.In tribo-electric series, materials are ranked from high to low in terms of the tendency for the material to lose electrons. If an object high up on this list (Glass, for exampl e) is rubbed with an object low down on the list (Teflon, for example), the glass will lose electrons to the teflon. The glass will, in this case, become positively charged and the teflon will become negatively charged. Materials in the middle of the list (steel and wood, for example) are items those do not have a strong tendency to give up or accept electrons.If human hair is rubbed with amber, how those will be charged?

Read the following text and answer the following questions on the basis of the same:Tribo-electric series: The tribo-electric series is a list that ranks materials according to their tendency to gain or lose electrons. The process of electron transfer as a result of two objects coming into contact with one another and then separating is called tribo-electric charging. During such an interaction, one of the two objects will always gain electrons (becoming negatively charge d) and the other object will lose electrons (becoming positively charged). The relative position of the two objects on the tribo-electric series will define which object gains electrons and which object loses electrons.In tribo-electric series, materials are ranked from high to low in terms of the tendency for the material to lose electrons. If an object high up on this list (Glass, for exampl e) is rubbed with an object low down on the list (Teflon, for example), the glass will lose electrons to the teflon. The glass will, in this case, become positively charged and the teflon will become negatively charged. Materials in the middle of the list (steel and wood, for example) are items those do not have a strong tendency to give up or accept electrons.Materials in the upper position has _____ tendency to become positively charged.

The equivalent emf of two cells (with ε1> ε2) in series if we connect two negative electrodes of adjacent cells isa)εequivalent =b)εequivalent =c)εequivalent =ε2 -ε1 (ε1 >ε2)d)εequivalent =ε1-ε2(ε1 >ε2)Correct answer is option 'D'. Can you explain this answer?
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The equivalent emf of two cells (with ε1> ε2) in series if we connect two negative electrodes of adjacent cells isa)εequivalent =b)εequivalent =c)εequivalent =ε2 -ε1 (ε1 >ε2)d)εequivalent =ε1-ε2(ε1 >ε2)Correct answer is option 'D'. Can you explain this answer? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about The equivalent emf of two cells (with ε1> ε2) in series if we connect two negative electrodes of adjacent cells isa)εequivalent =b)εequivalent =c)εequivalent =ε2 -ε1 (ε1 >ε2)d)εequivalent =ε1-ε2(ε1 >ε2)Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 12 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The equivalent emf of two cells (with ε1> ε2) in series if we connect two negative electrodes of adjacent cells isa)εequivalent =b)εequivalent =c)εequivalent =ε2 -ε1 (ε1 >ε2)d)εequivalent =ε1-ε2(ε1 >ε2)Correct answer is option 'D'. Can you explain this answer?.
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