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The electric field in a region of space is spherically symmetric and radially outward. The flux of electric field through a sphere of radius r, centred at orgin is flux =kr^2. which following is the correct relation between electric field strength with radial distance r from origin ?
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The electric field in a region of space is spherically symmetric and r...
- **Relation between Electric Field Strength and Radial Distance**
Electric field flux through a sphere of radius r, centered at the origin, is given by flux = kr^2. This implies that the electric field strength E at a distance r from the origin is directly proportional to the radius squared.
- **Mathematical Explanation**
The flux of an electric field through a closed surface is proportional to the charge enclosed by the surface. In this case, the closed surface is a sphere centered at the origin. The flux through this sphere is given by flux = kr^2.
According to Gauss's law, the flux of an electric field through a closed surface is equal to the total charge enclosed divided by the permittivity of free space (ε₀). Since the electric field is radially outward and spherically symmetric, the flux through the sphere is proportional to the square of the radius.
Therefore, the electric field strength E at a distance r from the origin can be expressed as E = Ar, where A is a constant of proportionality. This indicates that the electric field strength is directly proportional to the radial distance r from the origin.
In conclusion, the correct relation between electric field strength and radial distance r from the origin is E ∝ r. This implies that the electric field strength increases linearly with the radial distance from the origin.
Electric field flux through a sphere of radius r, centered at the origin, is given by flux = kr^2. This implies that the electric field strength E at a distance r from the origin is directly proportional to the radius squared.
- **Mathematical Explanation**
The flux of an electric field through a closed surface is proportional to the charge enclosed by the surface. In this case, the closed surface is a sphere centered at the origin. The flux through this sphere is given by flux = kr^2.
According to Gauss's law, the flux of an electric field through a closed surface is equal to the total charge enclosed divided by the permittivity of free space (ε₀). Since the electric field is radially outward and spherically symmetric, the flux through the sphere is proportional to the square of the radius.
Therefore, the electric field strength E at a distance r from the origin can be expressed as E = Ar, where A is a constant of proportionality. This indicates that the electric field strength is directly proportional to the radial distance r from the origin.
In conclusion, the correct relation between electric field strength and radial distance r from the origin is E ∝ r. This implies that the electric field strength increases linearly with the radial distance from the origin.
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The electric field in a region of space is spherically symmetric and radially outward. The flux of electric field through a sphere of radius r, centred at orgin is flux =kr^2. which following is the correct relation between electric field strength with radial distance r from origin ?
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The electric field in a region of space is spherically symmetric and radially outward. The flux of electric field through a sphere of radius r, centred at orgin is flux =kr^2. which following is the correct relation between electric field strength with radial distance r from origin ? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The electric field in a region of space is spherically symmetric and radially outward. The flux of electric field through a sphere of radius r, centred at orgin is flux =kr^2. which following is the correct relation between electric field strength with radial distance r from origin ? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The electric field in a region of space is spherically symmetric and radially outward. The flux of electric field through a sphere of radius r, centred at orgin is flux =kr^2. which following is the correct relation between electric field strength with radial distance r from origin ?.
The electric field in a region of space is spherically symmetric and radially outward. The flux of electric field through a sphere of radius r, centred at orgin is flux =kr^2. which following is the correct relation between electric field strength with radial distance r from origin ? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The electric field in a region of space is spherically symmetric and radially outward. The flux of electric field through a sphere of radius r, centred at orgin is flux =kr^2. which following is the correct relation between electric field strength with radial distance r from origin ? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The electric field in a region of space is spherically symmetric and radially outward. The flux of electric field through a sphere of radius r, centred at orgin is flux =kr^2. which following is the correct relation between electric field strength with radial distance r from origin ?.
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