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Two point charges of +4 μC and -6 μC are separated by a distance of 20 cm in air. At what point, on the line joining the two charges from charge +4 μC, the electric potential will be zero?
- a)6 cm
- b)8 cm
- c)10 cm
- d)12 cm
Correct answer is option 'B'. Can you explain this answer?
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Two point charges of +4 μC and -6 μC are separated by a distance of 20...
Understanding the Problem:
Two point charges of +4 μC and -6 μC are separated by a distance of 20 cm in air. We need to find the point, on the line joining the two charges from charge +4 μC, where the electric potential will be zero.
Concept of Electric Potential:
Electric potential is a scalar quantity that determines the potential energy of a charged particle at a point in an electric field. It is given by the formula V = k * (q / r), where V is the electric potential, k is the electrostatic constant, q is the charge, and r is the distance from the charge.
Calculating Electric Potential:
1. Let's assume the point where the electric potential is zero is at a distance x from the +4 μC charge.
2. The electric potential at this point due to the +4 μC charge is V1 = k * (4 μC) / (x).
3. The electric potential at this point due to the -6 μC charge is V2 = k * (-6 μC) / (20 cm - x).
4. Since the total electric potential is zero, V1 + V2 = 0.
5. Substituting the values and solving the equation, we get x = 8 cm.
Therefore, at a distance of 8 cm from the +4 μC charge on the line joining the two charges, the electric potential will be zero.
Two point charges of +4 μC and -6 μC are separated by a distance of 20 cm in air. We need to find the point, on the line joining the two charges from charge +4 μC, where the electric potential will be zero.
Concept of Electric Potential:
Electric potential is a scalar quantity that determines the potential energy of a charged particle at a point in an electric field. It is given by the formula V = k * (q / r), where V is the electric potential, k is the electrostatic constant, q is the charge, and r is the distance from the charge.
Calculating Electric Potential:
1. Let's assume the point where the electric potential is zero is at a distance x from the +4 μC charge.
2. The electric potential at this point due to the +4 μC charge is V1 = k * (4 μC) / (x).
3. The electric potential at this point due to the -6 μC charge is V2 = k * (-6 μC) / (20 cm - x).
4. Since the total electric potential is zero, V1 + V2 = 0.
5. Substituting the values and solving the equation, we get x = 8 cm.
Therefore, at a distance of 8 cm from the +4 μC charge on the line joining the two charges, the electric potential will be zero.
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Two point charges of +4 μC and -6 μC are separated by a distance of 20 cm in air. At what point, on the line joining the two charges from charge +4 μC, the electric potential will be zero?a)6 cmb)8 cmc)10 cmd)12 cmCorrect answer is option 'B'. Can you explain this answer?
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