JEE Exam > JEE Questions > a)b)1c)0d)none of these.Correct answer is opt...
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- a)
- b)1
- c)0
- d)none of these.
Correct answer is option 'B'. Can you explain this answer?
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a)b)1c)0d)none of these.Correct answer is option 'B'. Can you explain ...
sin-1√3/5 = A
Sin A = √3/5 , cos A = √22/5
Therefore Cos-1√3/5 = B
Cos B = √3/5 , sin B = √22/5
sin(A+B) = sinA cosB + cosA sinB
= √3/5 * √3/5 + √22/5 * √22/5
= 3/25 * 22/25
= 25/25
= 1
Sin A = √3/5 , cos A = √22/5
Therefore Cos-1√3/5 = B
Cos B = √3/5 , sin B = √22/5
sin(A+B) = sinA cosB + cosA sinB
= √3/5 * √3/5 + √22/5 * √22/5
= 3/25 * 22/25
= 25/25
= 1
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a)b)1c)0d)none of these.Correct answer is option 'B'. Can you explain ...
sin-1√3/5 = A
Sin A = √3/5 , cos A = √22/5
Therefore Cos-1√3/5 = B
Cos B = √3/5 , sin B = √22/5
sin(A+B) = sinA cosB + cosA sinB
= √3/5 * √3/5 + √22/5 * √22/5
= 3/25 * 22/25
= 25/25
= 1
Sin A = √3/5 , cos A = √22/5
Therefore Cos-1√3/5 = B
Cos B = √3/5 , sin B = √22/5
sin(A+B) = sinA cosB + cosA sinB
= √3/5 * √3/5 + √22/5 * √22/5
= 3/25 * 22/25
= 25/25
= 1
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a)b)1c)0d)none of these.Correct answer is option 'B'. Can you explain ...
Answer is B If sin A=√3/5 cos B=√3/5 We can find sin B and cos A After finding the values we use sin(A+B)
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a)b)1c)0d)none of these.Correct answer is option 'B'. Can you explain this answer?
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