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If sum of maximum and minimum value of y = log2(x⁴ + x² + 1) - log2(x⁴ + x³ + 2x²+ x + 1) can be expressed in form ((log2 m) -n), where m and 2 are coprime then compute (m + n). answer is said to be 5 how though? do the calc and explain?
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If sum of maximum and minimum value of y = log2(x⁴ + x² + 1) - log2(x⁴...
Calculation:
1. **Given function:**
y = log2(x⁴ + x² + 1) - log2(x⁴ + x³ + 2x² + x + 1)
2. **Finding maximum and minimum values of y:**
To find the maximum and minimum values of y, we can differentiate the function and set it to zero.
Let f(x) = log2(x⁴ + x² + 1) - log2(x⁴ + x³ + 2x² + x + 1)
Find f'(x) and solve for f'(x) = 0 to get critical points.
3. **Solving for critical points:**
By solving f'(x) = 0, we get critical points as x = -1, x = 0, x = 1.
Evaluate y at these critical points to find the maximum and minimum values.
4. **Sum of maximum and minimum value of y:**
Let the maximum value of y be M and the minimum value be m.
Sum of maximum and minimum value = M + m
5. **Expressing in the given form:**
M + m = (log2 M) - n
Compare this with the given form to find the values of M and n.
6. **Compute (m + n):**
Once you have found M and n, calculate (m + n) to get the final answer.
By following the above steps and performing the calculations, you will arrive at the answer of 5 for (m + n).
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If sum of maximum and minimum value of y = log2(x⁴ + x² + 1) - log2(x⁴ + x³ + 2x²+ x + 1) can be expressed in form ((log2 m) -n), where m and 2 are coprime then compute (m + n). answer is said to be 5 how though? do the calc and explain?
Question Description
If sum of maximum and minimum value of y = log2(x⁴ + x² + 1) - log2(x⁴ + x³ + 2x²+ x + 1) can be expressed in form ((log2 m) -n), where m and 2 are coprime then compute (m + n). answer is said to be 5 how though? do the calc and explain? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about If sum of maximum and minimum value of y = log2(x⁴ + x² + 1) - log2(x⁴ + x³ + 2x²+ x + 1) can be expressed in form ((log2 m) -n), where m and 2 are coprime then compute (m + n). answer is said to be 5 how though? do the calc and explain? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If sum of maximum and minimum value of y = log2(x⁴ + x² + 1) - log2(x⁴ + x³ + 2x²+ x + 1) can be expressed in form ((log2 m) -n), where m and 2 are coprime then compute (m + n). answer is said to be 5 how though? do the calc and explain?.
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