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The time taken for 90% of a first order reaction to complete is approximately
  • a)
    1•1 times that of half-life
  • b)
    2•2 times that of half-life
  • c)
    3•3 times that of half-life
  • d)
    4•4 times that of half-life
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
The time taken for 90% of a first order reaction to complete is approx...
Explanation:

First Order Reaction:
- A first order reaction is a reaction in which the rate of reaction is directly proportional to the concentration of a single reactant.
- The integrated rate law for a first order reaction is: ln([A]t/[A]0) = -kt, where [A]t is the concentration of the reactant at time t, [A]0 is the initial concentration, k is the rate constant, and t is time.

Time taken for 90% completion:
- For a first order reaction, the time taken for a certain percentage of the reaction to complete can be calculated using the equation: t90% = (2.303/k) * log([A]0/[A]0 - 0.9[A]0).
- For 90% completion, [A]t = 0.1[A]0.

Relation to Half-life:
- The half-life of a first order reaction is defined as the time taken for the concentration of the reactant to reduce to half of its initial value.
- The half-life of a first order reaction is given by: t1/2 = 0.693/k.

Comparison:
- The time taken for 90% of a first order reaction to complete is approximately 3.3 times the half-life of the reaction. This can be understood by comparing the equations for t90% and t1/2.
- Therefore, the correct answer is option 'c) 3.3 times that of half-life'.
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The time taken for 90% of a first order reaction to complete is approximatelya)1•1 times that of half-lifeb)2•2 times that of half-lifec)3•3 times that of half-lifed)4•4 times that of half-lifeCorrect answer is option 'C'. Can you explain this answer?
Question Description
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