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Direction: Four pairs of numbers have been given, out of which three are alike in some manner, while one is different.    (SSC Stenographer 2018)
Choose out the odd one.
  • a)
    4925 : 35
  • b)
    1625 : 9
  • c)
    4964 : 15
  • d)
    1681 : 13
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
Direction: Four pairs of numbers have been given, out of which three a...
(a) 4925 : 35 ⇒ √49 x √25 = 7 ´ 5= 35
(b) 1625 : 9 ⇒ √ 16 + √25 = 4 + 5= 9
(c)  4964 :15 ⇒ √ 49 + √64 = 7 + 8= 15
(d)  1681:13 ⇒ √ 16 + √81 = 4 + 9=13
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Community Answer
Direction: Four pairs of numbers have been given, out of which three a...
Odd One Out:

a) 4925 : 35

b) 1625 : 9

c) 4964 : 15

d) 1681 : 13
The odd one out in this group is option 'a' (4925 : 35) because it is the only pair where the second number is not a perfect square of the first number.
Let's break down each pair:

a) 4925 : 35 - 35 is not a perfect square of 4925

b) 1625 : 9 - 9 is a perfect square of 1625 (9 x 9 = 81)

c) 4964 : 15 - 15 is not a perfect square of 4964

d) 1681 : 13 - 13 is a perfect square of 1681 (13 x 13 = 169)
Therefore, option 'a' (4925 : 35) is the odd one out in this group as it does not follow the pattern of having the second number as a perfect square of the first number.
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Direction: Four pairs of numbers have been given, out of which three are alike in some manner, while one is different. (SSC Stenographer 2018)Choose out the odd one.a)4925 : 35b)1625 : 9c)4964 : 15d)1681 : 13Correct answer is option 'A'. Can you explain this answer?
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