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A particle, after starting from rest , experiences, constant acceleration for 20 seconds. If it covers a distance of S1, in first 10 seconds and distance S2 in next 10 sec, then
- a)S2 = S1/2
- b)S2 = S1
- c)S2 = 2S1
- d)S2 = 3S1
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
A particle, after starting from rest , experiences, constant accelerat...
Let constant acceleration is a
distance travels in 20 seconds
s = 0*20+a*20²/2
s = 200a -------------(1)
distance travels in first 10 seconds
s1 = 0*10+a*10²/2
s1 = 50a -----------------(2)
distance travels in next 10 seconds
s2 = s-s1
s2 = 200a-50a = 150a ----------------(3)
s2/s1 = 150a/50a = 3
Most Upvoted Answer
A particle, after starting from rest , experiences, constant accelerat...
Explanation:
First, let's analyze the given information:
- The particle starts from rest, meaning its initial velocity is zero.
- The particle experiences constant acceleration for 20 seconds.
- The distance covered in the first 10 seconds is denoted as S1.
- The distance covered in the next 10 seconds is denoted as S2.
Using the equations of motion:
We can use the equations of motion to solve this problem. The equation relating distance (S), initial velocity (u), time (t), and acceleration (a) is:
S = ut + (1/2)at²
Given that the particle starts from rest (u = 0), the equation simplifies to:
S = (1/2)at²
Using this equation, we can calculate the distances S1 and S2.
Calculating S1:
For the first 10 seconds, we have:
S1 = (1/2)at²
Since the particle experiences constant acceleration for 20 seconds, we can substitute the value of time (t) with 10 seconds:
S1 = (1/2)a(10)²
S1 = 50a
Calculating S2:
For the next 10 seconds, we have:
S2 = (1/2)at²
Since the particle experiences constant acceleration for 20 seconds, the time (t) in this case would be 10 seconds as well:
S2 = (1/2)a(10)²
S2 = 50a
Comparing S2 to S1:
If we compare the expressions for S1 and S2, we can see that they are equal:
S1 = 50a
S2 = 50a
Therefore, S2 is equal to S1.
Conclusion:
Based on the calculations, it can be concluded that the distance covered in the next 10 seconds (S2) is equal to 3 times the distance covered in the first 10 seconds (S1). Hence, the correct answer is option D: S2 = 3S1.
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Community Answer
A particle, after starting from rest , experiences, constant accelerat...
S=ut + 1/2 at^2 S1= 0 + 1/2 a * 100 =50a S2+ s1 = 0+ 1/2 *400a =200a S2+ 50a= 200a S2= 150a now , S2/S1 = 150a/50a = 3 so, S2= 3 S1
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A particle, after starting from rest , experiences, constant acceleration for 20 seconds. If it covers a distance of S1, in first 10 seconds and distance S2in next 10 sec, thena)S2= S1/2b)S2= S1c)S2= 2S1d)S2= 3S1Correct answer is option 'D'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A particle, after starting from rest , experiences, constant acceleration for 20 seconds. If it covers a distance of S1, in first 10 seconds and distance S2in next 10 sec, thena)S2= S1/2b)S2= S1c)S2= 2S1d)S2= 3S1Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A particle, after starting from rest , experiences, constant acceleration for 20 seconds. If it covers a distance of S1, in first 10 seconds and distance S2in next 10 sec, thena)S2= S1/2b)S2= S1c)S2= 2S1d)S2= 3S1Correct answer is option 'D'. Can you explain this answer?.
A particle, after starting from rest , experiences, constant acceleration for 20 seconds. If it covers a distance of S1, in first 10 seconds and distance S2in next 10 sec, thena)S2= S1/2b)S2= S1c)S2= 2S1d)S2= 3S1Correct answer is option 'D'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A particle, after starting from rest , experiences, constant acceleration for 20 seconds. If it covers a distance of S1, in first 10 seconds and distance S2in next 10 sec, thena)S2= S1/2b)S2= S1c)S2= 2S1d)S2= 3S1Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A particle, after starting from rest , experiences, constant acceleration for 20 seconds. If it covers a distance of S1, in first 10 seconds and distance S2in next 10 sec, thena)S2= S1/2b)S2= S1c)S2= 2S1d)S2= 3S1Correct answer is option 'D'. Can you explain this answer?.
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A particle, after starting from rest , experiences, constant acceleration for 20 seconds. If it covers a distance of S1, in first 10 seconds and distance S2in next 10 sec, thena)S2= S1/2b)S2= S1c)S2= 2S1d)S2= 3S1Correct answer is option 'D'. Can you explain this answer?, a detailed solution for A particle, after starting from rest , experiences, constant acceleration for 20 seconds. If it covers a distance of S1, in first 10 seconds and distance S2in next 10 sec, thena)S2= S1/2b)S2= S1c)S2= 2S1d)S2= 3S1Correct answer is option 'D'. Can you explain this answer? has been provided alongside types of A particle, after starting from rest , experiences, constant acceleration for 20 seconds. If it covers a distance of S1, in first 10 seconds and distance S2in next 10 sec, thena)S2= S1/2b)S2= S1c)S2= 2S1d)S2= 3S1Correct answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
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