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If ‘X’ is a random variable, taking values ‘x’, probability of success and failure being ‘p’ and ‘q’ respectively and ‘n’ trials being conducted, then what is the probability that ‘X’ takes values ‘x’? Use Binomial Distributiona)P(X = x) =nCxpxqxb)P(X = x) =nCxpxq(n-x)c)P(X = x) =xCnqxp(n-x)d)P(x = x) =xCnpnqxCorrect answer is option 'B'. Can you explain this answer? for Mathematics 2024 is part of Mathematics preparation. The Question and answers have been prepared
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the Mathematics exam syllabus. Information about If ‘X’ is a random variable, taking values ‘x’, probability of success and failure being ‘p’ and ‘q’ respectively and ‘n’ trials being conducted, then what is the probability that ‘X’ takes values ‘x’? Use Binomial Distributiona)P(X = x) =nCxpxqxb)P(X = x) =nCxpxq(n-x)c)P(X = x) =xCnqxp(n-x)d)P(x = x) =xCnpnqxCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Mathematics 2024 Exam.
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If ‘X’ is a random variable, taking values ‘x’, probability of success and failure being ‘p’ and ‘q’ respectively and ‘n’ trials being conducted, then what is the probability that ‘X’ takes values ‘x’? Use Binomial Distributiona)P(X = x) =nCxpxqxb)P(X = x) =nCxpxq(n-x)c)P(X = x) =xCnqxp(n-x)d)P(x = x) =xCnpnqxCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for If ‘X’ is a random variable, taking values ‘x’, probability of success and failure being ‘p’ and ‘q’ respectively and ‘n’ trials being conducted, then what is the probability that ‘X’ takes values ‘x’? Use Binomial Distributiona)P(X = x) =nCxpxqxb)P(X = x) =nCxpxq(n-x)c)P(X = x) =xCnqxp(n-x)d)P(x = x) =xCnpnqxCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of If ‘X’ is a random variable, taking values ‘x’, probability of success and failure being ‘p’ and ‘q’ respectively and ‘n’ trials being conducted, then what is the probability that ‘X’ takes values ‘x’? Use Binomial Distributiona)P(X = x) =nCxpxqxb)P(X = x) =nCxpxq(n-x)c)P(X = x) =xCnqxp(n-x)d)P(x = x) =xCnpnqxCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice If ‘X’ is a random variable, taking values ‘x’, probability of success and failure being ‘p’ and ‘q’ respectively and ‘n’ trials being conducted, then what is the probability that ‘X’ takes values ‘x’? Use Binomial Distributiona)P(X = x) =nCxpxqxb)P(X = x) =nCxpxq(n-x)c)P(X = x) =xCnqxp(n-x)d)P(x = x) =xCnpnqxCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice Mathematics tests.