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If ‘X’ is a random variable, taking values ‘x’, probability of success and failure being ‘p’ and ‘q’ respectively and ‘n’ trials being conducted, then what is the probability that ‘X’ takes values ‘x’? Use Binomial Distribution
  • a)
    P(X = x) = nCx px qx
  • b)
    P(X = x) = nCx px q(n-x)
  • c)
    P(X = x) = xCn qx p(n-x)
  • d)
    P(x = x) = xCn pn qx
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
If ‘X’ is a random variable, taking values ‘x’...
It is the formula for Binomial Distribution that is asked here which is given by P(X = x) = nCx px q(n - x).
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If ‘X’ is a random variable, taking values ‘x’, probability of success and failure being ‘p’ and ‘q’ respectively and ‘n’ trials being conducted, then what is the probability that ‘X’ takes values ‘x’? Use Binomial Distributiona)P(X = x) =nCxpxqxb)P(X = x) =nCxpxq(n-x)c)P(X = x) =xCnqxp(n-x)d)P(x = x) =xCnpnqxCorrect answer is option 'B'. Can you explain this answer?
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