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A coin is based so that a head is twice as likely to occur as a tail. If the coin is tossed 3 times, then the probability of getting two tails and one head is-
  • a)
    2/9
  • b)
    1/9
  • c)
    2/27
  • d)
    1/27
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
A coin is based so that a head is twice as likely to occur as a tail. ...
 Let probability of tail is 1/3
⇒ Probability of getting head =2/3
∴ Probability of getting 2 tails and 1 head
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Most Upvoted Answer
A coin is based so that a head is twice as likely to occur as a tail. ...
Understanding the Coin Bias
The coin is biased such that heads (H) are twice as likely to occur as tails (T). This means the probabilities are:
- Probability of getting a head (P(H)) = 2/3
- Probability of getting a tail (P(T)) = 1/3
Calculating the Probability of 2 Tails and 1 Head
When tossing the coin 3 times, we need to find the probability of getting exactly 2 tails and 1 head.
Possible Outcomes
The possible sequences for getting 2 tails and 1 head are:
- TTH
- THT
- HTT
Calculating Individual Probabilities
For each of these sequences, the probability can be calculated as follows:
- Probability of TTH = P(T) * P(T) * P(H) = (1/3) * (1/3) * (2/3) = 2/27
- Probability of THT = P(T) * P(H) * P(T) = (1/3) * (2/3) * (1/3) = 2/27
- Probability of HTT = P(H) * P(T) * P(T) = (2/3) * (1/3) * (1/3) = 2/27
Total Probability
Now, add the probabilities of all three sequences:
- Total Probability = P(TTH) + P(THT) + P(HTT)
- Total Probability = 2/27 + 2/27 + 2/27 = 6/27 = 2/9
Conclusion
Therefore, the probability of getting exactly 2 tails and 1 head when tossing the biased coin three times is 2/9. The correct answer is option 'A'.
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