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When unpolarized light is incident at an angle of 60° on a transparent medium from air. The reflected ray is completely polarized. The angle of refraction in the medium is
- a)30º
- b)60º
- c)90º
- d)45º
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
When unpolarized light is incident at an angle of 60°on a transpar...
By Brewster's law
At complete reflection refracted ray and reflected ray are perpendicular.
Most Upvoted Answer
When unpolarized light is incident at an angle of 60°on a transpar...
Understanding Polarization of Light
When unpolarized light strikes a transparent medium, the angle at which it gets completely polarized during reflection is known as Brewster's angle. For a medium with a refractive index \( n \), Brewster's angle (\( \theta_B \)) can be calculated using the formula:
\[
\theta_B = \tan^{-1}(n)
\]
Given Information
- Angle of incidence \( \theta_i = 60^\circ \)
- The reflected ray is completely polarized.
Finding the Refractive Index
Using the relationship of Brewster's angle, we have:
\[
\theta_B = 60^\circ
\]
This implies:
\[
n = \tan(60^\circ) = \sqrt{3} \approx 1.732
\]
Applying Snell's Law
To find the angle of refraction (\( \theta_r \)) in the medium, we can apply Snell's Law:
\[
n_1 \sin(\theta_i) = n_2 \sin(\theta_r)
\]
Where:
- \( n_1 = 1 \) (for air)
- \( n_2 = \sqrt{3} \)
- \( \theta_i = 60^\circ \)
Substituting the values:
\[
1 \cdot \sin(60^\circ) = \sqrt{3} \cdot \sin(\theta_r)
\]
This simplifies to:
\[
\frac{\sqrt{3}}{2} = \sqrt{3} \sin(\theta_r)
\]
Dividing both sides by \( \sqrt{3} \):
\[
\frac{1}{2} = \sin(\theta_r)
\]
Calculating Angle of Refraction
From the equation:
\[
\theta_r = \sin^{-1}\left(\frac{1}{2}\right) = 30^\circ
\]
Thus, the angle of refraction in the medium is:
Correct Answer
- **Option (a) 30°**
When unpolarized light strikes a transparent medium, the angle at which it gets completely polarized during reflection is known as Brewster's angle. For a medium with a refractive index \( n \), Brewster's angle (\( \theta_B \)) can be calculated using the formula:
\[
\theta_B = \tan^{-1}(n)
\]
Given Information
- Angle of incidence \( \theta_i = 60^\circ \)
- The reflected ray is completely polarized.
Finding the Refractive Index
Using the relationship of Brewster's angle, we have:
\[
\theta_B = 60^\circ
\]
This implies:
\[
n = \tan(60^\circ) = \sqrt{3} \approx 1.732
\]
Applying Snell's Law
To find the angle of refraction (\( \theta_r \)) in the medium, we can apply Snell's Law:
\[
n_1 \sin(\theta_i) = n_2 \sin(\theta_r)
\]
Where:
- \( n_1 = 1 \) (for air)
- \( n_2 = \sqrt{3} \)
- \( \theta_i = 60^\circ \)
Substituting the values:
\[
1 \cdot \sin(60^\circ) = \sqrt{3} \cdot \sin(\theta_r)
\]
This simplifies to:
\[
\frac{\sqrt{3}}{2} = \sqrt{3} \sin(\theta_r)
\]
Dividing both sides by \( \sqrt{3} \):
\[
\frac{1}{2} = \sin(\theta_r)
\]
Calculating Angle of Refraction
From the equation:
\[
\theta_r = \sin^{-1}\left(\frac{1}{2}\right) = 30^\circ
\]
Thus, the angle of refraction in the medium is:
Correct Answer
- **Option (a) 30°**
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When unpolarized light is incident at an angle of 60°on a transparent medium from air. The reflected ray is completely polarized. The angle of refraction in the medium isa)30ºb)60ºc)90ºd)45ºCorrect answer is option 'A'. Can you explain this answer?
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When unpolarized light is incident at an angle of 60°on a transparent medium from air. The reflected ray is completely polarized. The angle of refraction in the medium isa)30ºb)60ºc)90ºd)45ºCorrect answer is option 'A'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about When unpolarized light is incident at an angle of 60°on a transparent medium from air. The reflected ray is completely polarized. The angle of refraction in the medium isa)30ºb)60ºc)90ºd)45ºCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for When unpolarized light is incident at an angle of 60°on a transparent medium from air. The reflected ray is completely polarized. The angle of refraction in the medium isa)30ºb)60ºc)90ºd)45ºCorrect answer is option 'A'. Can you explain this answer?.
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