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Correct answer is option 'B'. Can you explain this answer?
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a)b)c)d)Correct answer is option 'B'. Can you explain this ans...
The second ionization energy refers to the energy required to remove the electron from the corresponding monovalent cation of the respective atom.
It is expected to increase from left to right in the periodic table with the decrease in atomic size.
Since the Oxygen atom gets a stable electronic configuration, 2s22p3 after removing one electron, the O+ shows greater ionization energy than F+ as well as N+
Thus, correct order will be: O > F > N > C
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a)b)c)d)Correct answer is option 'B'. Can you explain this ans...
The second ionization energy refers to the energy required to remove the electron from the corresponding monovalent cation of the respective atom.
It is expected to increase from left to right in the periodic table with the decrease in atomic size.
Since the Oxygen atom gets a stable electronic configuration, 2s22p3 after removing one electron, the O+ shows greater ionization energy than F+ as well as N+
Thus, correct order will be: O > F > N > C
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a)b)c)d)Correct answer is option 'B'. Can you explain this ans...
O have 2nd highest ionisation energy (u must know the order F O N ) flourine have 1st highest ionisation energy It ask about 2nd ionisation energy thats why (oxygen )will have the highest 2nd ionisation energy then (flourine) then (nitrogen) nd then (carbon ) THEREFORE B is the correct option
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