The difference in the oxidation number of the two types of sulphur atoms in Na2S4O6 is .........[HTJEE2011]Correct answer is '7'. Can you explain this answer?

Question

Answer

Difference in oxidation number = 6 - (-1) = 7

Answer

Answer

Here 1 sulphur has charge +6 and 1 has -2

Answer

Answer

The oxidation number of an atom is a measure of the number of electrons it has gained or lost in a chemical compound. In the case of sulphur in Na2S4O6, there are two types of sulphur atoms present: one with a higher oxidation number and one with a lower oxidation number.

Higher oxidation number sulphur atoms:
- There are two higher oxidation number sulphur atoms in Na2S4O6.
- Let's assign the oxidation number of x to these sulphur atoms.
- Since the compound is neutral, the sum of the oxidation numbers of all the atoms must be zero.
- The two higher oxidation number sulphur atoms contribute 2x to the sum of the oxidation numbers.
- Therefore, 2x = 0, which gives x = 0.

Lower oxidation number sulphur atoms:
- There are four lower oxidation number sulphur atoms in Na2S4O6.
- Let's assign the oxidation number of y to these sulphur atoms.
- Similar to before, the sum of the oxidation numbers of all the atoms must be zero.
- The four lower oxidation number sulphur atoms contribute 4y to the sum of the oxidation numbers.
- Therefore, 4y = 0, which gives y = 0.

Difference in oxidation numbers:
- The difference in the oxidation numbers of the two types of sulphur atoms is given by x - y.
- Substituting the values we obtained earlier, the difference is 0 - 0 = 0.

Correct answer:
- According to the question, the correct answer is 7.
- However, the answer we obtained is 0, which contradicts the given correct answer.

Possible error or misunderstanding:
- It is possible that there is an error in the question or the correct answer provided.
- Alternatively, there may be a misunderstanding or misinterpretation of the compound or the oxidation numbers assigned to the sulphur atoms.

In conclusion, based on the information provided, the difference in the oxidation number of the two types of sulphur atoms in Na2S4O6 is not 7 as stated in the question. The correct answer could be different or there may be an error or misunderstanding involved.

Similar Class 11 Doubts

Direction (Q. Nos. 18 and 19) This section contains 2questions. when worked out will result in an integer from 0 to 9 (both inclusiv e)Q. has two types of sulphur atoms. What is the difference in the oxidation states of two types of sulphur atoms? Correct answer is '8'. Can you explain this answer?

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