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Suppose our school is 1 km away from our house, and we go to school in the morning, and in the afternoon we come back. Then, the total displacement for the entire trip is
- a)1 km
- b)2 km
- c)-1 km
- d)0 km
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
Suppose our school is 1 km away from our house, and we go to school in...
The displacement is 0 because the initial and final position are the same, i.e. the home, and hence, displacement is 0.
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Suppose our school is 1 km away from our house, and we go to school in...
**Explanation:**
Displacement is a vector quantity that refers to the change in position of an object from its initial position to its final position. It is defined by both magnitude and direction. In this case, we need to determine the total displacement for the entire trip from the house to the school and back.
To understand the concept of displacement, let's break down the journey into two parts: going to school in the morning and coming back in the afternoon.
**Going to School in the Morning:**
- Distance covered: 1 km (from the house to the school)
- Displacement: 1 km (magnitude) in the direction of the school (since we are moving towards the school)
**Coming Back in the Afternoon:**
- Distance covered: 1 km (from the school to the house)
- Displacement: 1 km (magnitude) in the direction of the house (since we are moving towards the house)
Now, let's calculate the total displacement for the entire trip by combining the individual displacements.
**Total Displacement:**
- Displacement to the school: 1 km (magnitude) in the direction of the school
- Displacement back to the house: 1 km (magnitude) in the direction of the house
Since the magnitude and direction of the displacements cancel each other out, the total displacement is zero.
**Therefore, the correct answer is option 'D' - 0 km.**
It's important to note that displacement is different from distance. Distance is a scalar quantity that refers to the total path length covered by an object, while displacement considers only the change in position from the initial to the final point. In this case, the distance covered is 2 km (1 km to the school + 1 km back to the house), but the displacement is zero because the final position is the same as the initial position.
Displacement is a vector quantity that refers to the change in position of an object from its initial position to its final position. It is defined by both magnitude and direction. In this case, we need to determine the total displacement for the entire trip from the house to the school and back.
To understand the concept of displacement, let's break down the journey into two parts: going to school in the morning and coming back in the afternoon.
**Going to School in the Morning:**
- Distance covered: 1 km (from the house to the school)
- Displacement: 1 km (magnitude) in the direction of the school (since we are moving towards the school)
**Coming Back in the Afternoon:**
- Distance covered: 1 km (from the school to the house)
- Displacement: 1 km (magnitude) in the direction of the house (since we are moving towards the house)
Now, let's calculate the total displacement for the entire trip by combining the individual displacements.
**Total Displacement:**
- Displacement to the school: 1 km (magnitude) in the direction of the school
- Displacement back to the house: 1 km (magnitude) in the direction of the house
Since the magnitude and direction of the displacements cancel each other out, the total displacement is zero.
**Therefore, the correct answer is option 'D' - 0 km.**
It's important to note that displacement is different from distance. Distance is a scalar quantity that refers to the total path length covered by an object, while displacement considers only the change in position from the initial to the final point. In this case, the distance covered is 2 km (1 km to the school + 1 km back to the house), but the displacement is zero because the final position is the same as the initial position.
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