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A journal bearing has a shaft diameter of 40 mm and a length of 40 mm. The shaft is rotating at 20 rad/s and the viscosity of the lubricant is 20 MPa-s. The clearance is 0.020 mm. The loss of torque due to the viscosity of the lubricant is approximately 
  • a)
    0.040 Nm
  • b)
    0.252 Nm
  • c)
    0.400 Nm
  • d)
    0.652 Nm
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
A journal bearing has a shaft diameter of 40 mm and a length of 40 mm....
Diameter of shaft (d) = 40 mm = 0.04 m
Length of shaft (L) = 40 mm = 0.04 m
Angular speed of shaft (ω)= 20 rad/s
Viscosity of fluid (μ) = 20 × 10−3 Pa-s
Clearance (dy) = 0.02 mm = 2 × 10−5 m
Velocity at periphery of shaft = u
= 0.04 N.m
Hence, the correct option is (a).
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Community Answer
A journal bearing has a shaft diameter of 40 mm and a length of 40 mm....
Calculation of Loss of Torque due to Viscosity of the Lubricant
- Given parameters:
- Shaft diameter (D): 40 mm
- Shaft length (L): 40 mm
- Shaft rotation speed (ω): 20 rad/s
- Viscosity of lubricant (μ): 20 MPa-s
- Clearance (C): 0.020 mm
- Calculate the radius of the journal bearing:
- Radius (r) = D/2 = 40/2 = 20 mm = 0.020 m
- Calculate the clearance ratio (ε):
- ε = C/r = 0.020/0.020 = 1
- Calculate the torque loss due to viscosity of the lubricant:
- Torque loss = 6πμLωr^2/ε = 6π(20x10^6)(0.040)(20)^2/1 = 0.040 Nm
Therefore, the loss of torque due to the viscosity of the lubricant is approximately 0.040 Nm, which corresponds to option 'A'.
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A journal bearing has a shaft diameter of 40 mm and a length of 40 mm. The shaft is rotating at 20 rad/s and the viscosity of the lubricant is 20 MPa-s. The clearance is 0.020 mm. The loss of torque due to the viscosity of the lubricant is approximatelya)0.040 Nmb)0.252 Nmc)0.400 Nmd)0.652 NmCorrect answer is option 'A'. Can you explain this answer?
Question Description
A journal bearing has a shaft diameter of 40 mm and a length of 40 mm. The shaft is rotating at 20 rad/s and the viscosity of the lubricant is 20 MPa-s. The clearance is 0.020 mm. The loss of torque due to the viscosity of the lubricant is approximatelya)0.040 Nmb)0.252 Nmc)0.400 Nmd)0.652 NmCorrect answer is option 'A'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A journal bearing has a shaft diameter of 40 mm and a length of 40 mm. The shaft is rotating at 20 rad/s and the viscosity of the lubricant is 20 MPa-s. The clearance is 0.020 mm. The loss of torque due to the viscosity of the lubricant is approximatelya)0.040 Nmb)0.252 Nmc)0.400 Nmd)0.652 NmCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A journal bearing has a shaft diameter of 40 mm and a length of 40 mm. The shaft is rotating at 20 rad/s and the viscosity of the lubricant is 20 MPa-s. The clearance is 0.020 mm. The loss of torque due to the viscosity of the lubricant is approximatelya)0.040 Nmb)0.252 Nmc)0.400 Nmd)0.652 NmCorrect answer is option 'A'. Can you explain this answer?.
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