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The area enclosed by velocity-time graph and the time axis will be equal to the magnitude of
- a)displacement
- b)speed
- c)acceleration
- d)distance
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
The area enclosed by velocity-time graph and the time axis will be equ...
Explanation:
Derivation:
Conclusion:
When an object is in motion, its velocity changes with time. The velocity-time graph shows the variation of velocity with time. The area enclosed by the velocity-time graph and the time axis represents the distance travelled by the object in a given time interval.
Derivation:
Let's consider an object moving with a variable velocity v(t) in a straight line. The velocity of the object at any instant t is given by:
v(t) = ds/dt
where s is the displacement of the object at time t. Integrating both sides, we get:
s = ∫v(t) dt
The integral of velocity with respect to time gives the displacement of the object. The area under the velocity-time graph represents the area of the region bounded by the graph, the time axis and the two vertical lines drawn at the beginning and end of the time interval.
Conclusion:
Therefore, the area enclosed by the velocity-time graph and the time axis represents the displacement of the object. Hence, option 'A' is the correct answer.
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The area enclosed by velocity-time graph and the time axis will be equ...
The area of velocity-time graph give us displcement
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