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A force of 20 N is applied on a body of mass 4 kg kept on a rough surface having coefficient of friction 0.1. Find acceleration of body. Take g = 10 m/s2
- a)7 m/s2
- b)4 m/s2
- c)9 m/s2
- d)6 m/s2
Correct answer is option 'B'. Can you explain this answer?
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A force of 20 N is applied on a body of mass 4 kg kept on a rough surf...
Given, force applied on the body, F = 20 N
Mass of the body, m = 4 kg
Coefficient of friction, μ = 0.1
Acceleration of the body, a = ?
We know that the force of friction, f = μN
where N is the normal force acting on the body.
The normal force, N = mg
where g is the acceleration due to gravity, given as 10 m/s2.
So, N = 4 × 10 = 40 N
The force of friction, f = 0.1 × 40 = 4 N
The net force acting on the body, Fnet = F - f
= 20 - 4
= 16 N
Using Newton's second law of motion, Fnet = ma
16 = 4a
a = 4 m/s2
Therefore, the acceleration of the body is 4 m/s2.
Hence, the correct answer is option B.
Mass of the body, m = 4 kg
Coefficient of friction, μ = 0.1
Acceleration of the body, a = ?
We know that the force of friction, f = μN
where N is the normal force acting on the body.
The normal force, N = mg
where g is the acceleration due to gravity, given as 10 m/s2.
So, N = 4 × 10 = 40 N
The force of friction, f = 0.1 × 40 = 4 N
The net force acting on the body, Fnet = F - f
= 20 - 4
= 16 N
Using Newton's second law of motion, Fnet = ma
16 = 4a
a = 4 m/s2
Therefore, the acceleration of the body is 4 m/s2.
Hence, the correct answer is option B.
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