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Directions: In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and give answer.
I. 3x2 – 21x + 36 = 0 
II. 5y2 – 25y + 30 = 0
  • a)
    if x > y
  • b)
    if x ≤ y 
  • c)
    if x ≥ y
  • d)
    if x < y
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
Directions: In each of these questions, two equations (I) and (II) are...
I. 3x2 – 21x + 36 = 0
3x2 – 12x – 9x + 36 = 0

II. 5y2 – 25y + 30 = 0
5y2 – 10y – 15y + 30 = 0

Answer: x ≥ y
Hence, Option C is correct.
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Community Answer
Directions: In each of these questions, two equations (I) and (II) are...
Given Equations:
I. 3x^2 – 21x + 36 = 0
II. 5y^2 – 25y + 30 = 0

Solution:

Equation I:
Factorizing the equation 3x^2 – 21x + 36 = 0, we get:
3x^2 – 9x – 12x + 36 = 0
3x(x – 3) – 12(x – 3) = 0
(3x – 12)(x – 3) = 0
x = 4 or x = 3

Equation II:
Factorizing the equation 5y^2 – 25y + 30 = 0, we get:
5y^2 – 15y – 10y + 30 = 0
5y(y – 3) – 10(y – 3) = 0
(5y – 10)(y – 3) = 0
y = 2 or y = 3

Comparing x and y:
x = 4 or 3
y = 2 or 3
Since x can be greater than or equal to y, the correct answer is option 'C'.
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Directions: In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and give answer.I. 3x2 – 21x + 36 = 0II. 5y2 – 25y + 30 = 0a)if x > yb)if x ≤ yc)if x ≥ yd)if x < yCorrect answer is option 'C'. Can you explain this answer?
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