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A car is accelerated uniformly from 36 km per hour to 90 km per hour in 3 seconds. Calculate: (a) The acceleration of car (b)The distance covered by the car in that time.?
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A car is accelerated uniformly from 36 km per hour to 90 km per hour i...
Acceleration Calculation:
Acceleration (a) can be calculated using the formula:
a = (v_f - v_i) / t
Where:
a = acceleration
v_f = final velocity = 90 km/h = 25 m/s (1 km/h = 5/18 m/s)
v_i = initial velocity = 36 km/h = 10 m/s
t = time taken = 3 seconds
Substitute the values into the formula:
a = (25 - 10) / 3
a = 15 / 3
a = 5 m/s²
Therefore, the acceleration of the car is 5 m/s².
Distance Calculation:
To calculate the distance covered by the car, we can use the equation:
s = v_i * t + 0.5 * a * t^2
Where:
s = distance covered
v_i = initial velocity = 10 m/s
a = acceleration = 5 m/s²
t = time taken = 3 seconds
Substitute the values into the formula:
s = 10 * 3 + 0.5 * 5 * 3^2
s = 30 + 0.5 * 5 * 9
s = 30 + 0.5 * 45
s = 30 + 22.5
s = 52.5 meters
Therefore, the distance covered by the car in 3 seconds is 52.5 meters.
Acceleration (a) can be calculated using the formula:
a = (v_f - v_i) / t
Where:
a = acceleration
v_f = final velocity = 90 km/h = 25 m/s (1 km/h = 5/18 m/s)
v_i = initial velocity = 36 km/h = 10 m/s
t = time taken = 3 seconds
Substitute the values into the formula:
a = (25 - 10) / 3
a = 15 / 3
a = 5 m/s²
Therefore, the acceleration of the car is 5 m/s².
Distance Calculation:
To calculate the distance covered by the car, we can use the equation:
s = v_i * t + 0.5 * a * t^2
Where:
s = distance covered
v_i = initial velocity = 10 m/s
a = acceleration = 5 m/s²
t = time taken = 3 seconds
Substitute the values into the formula:
s = 10 * 3 + 0.5 * 5 * 3^2
s = 30 + 0.5 * 5 * 9
s = 30 + 0.5 * 45
s = 30 + 22.5
s = 52.5 meters
Therefore, the distance covered by the car in 3 seconds is 52.5 meters.
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A car is accelerated uniformly from 36 km per hour to 90 km per hour in 3 seconds. Calculate: (a) The acceleration of car (b)The distance covered by the car in that time.?
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A car is accelerated uniformly from 36 km per hour to 90 km per hour in 3 seconds. Calculate: (a) The acceleration of car (b)The distance covered by the car in that time.? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about A car is accelerated uniformly from 36 km per hour to 90 km per hour in 3 seconds. Calculate: (a) The acceleration of car (b)The distance covered by the car in that time.? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A car is accelerated uniformly from 36 km per hour to 90 km per hour in 3 seconds. Calculate: (a) The acceleration of car (b)The distance covered by the car in that time.?.
A car is accelerated uniformly from 36 km per hour to 90 km per hour in 3 seconds. Calculate: (a) The acceleration of car (b)The distance covered by the car in that time.? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about A car is accelerated uniformly from 36 km per hour to 90 km per hour in 3 seconds. Calculate: (a) The acceleration of car (b)The distance covered by the car in that time.? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A car is accelerated uniformly from 36 km per hour to 90 km per hour in 3 seconds. Calculate: (a) The acceleration of car (b)The distance covered by the car in that time.?.
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