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Two numbers when divided by a certain divisor gives remainders 13 & 9 respectively then their sum is divided by same divisor the remainder is 3 the divisor is give by?
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Two numbers when divided by a certain divisor gives remainders 13 & 9 ...
Given Information:
- Two numbers give remainders 13 and 9 respectively when divided by a certain divisor.
- When the sum of these two numbers is divided by the same divisor, the remainder is 3.

To Find:
- The divisor.

Solution:

Let's denote:
- The divisor as D.
- The two numbers as A and B.

Expressing the given information:
- A = Dx + 13 (where x is an integer)
- B = Dy + 9 (where y is an integer)
- (A + B) = Dz + 3 (where z is an integer)

Expressing the sum of A and B:
- A + B = Dx + 13 + Dy + 9
- A + B = D(x + y) + 22

Expressing the given information about the sum:
- D(x + y) + 22 = Dz + 3
- D(x + y) = Dz - 19

Since the divisor D will divide (A + B) with a remainder of 3:
- D(x + y) = Dz - 19 = Dk + 3
- D(z - k) = 22
- D must be a divisor of 22.

Therefore, the possible values for the divisor D are:
- 1, 2, 11, 22

Conclusion:
- The divisor can be 1, 2, 11, or 22.
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Two numbers when divided by a certain divisor gives remainders 13 & 9 respectively then their sum is divided by same divisor the remainder is 3 the divisor is give by?
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