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If the co-ordinates of three vertices of a square are A(0, 0), B(-3,0) and C(0,3), then the co-ordinates of its fourth vertex is?
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If the co-ordinates of three vertices of a square are A(0, 0), B(-3,0)...
Find the Co-ordinates of the Fourth Vertex of the Square:
First, let's plot the given points A(0, 0), B(-3, 0), and C(0, 3) on a coordinate plane.
- Point A(0, 0) is at the origin.
- Point B(-3, 0) is 3 units to the left of the origin.
- Point C(0, 3) is 3 units above the origin.
Now, we know that a square has four equal sides and each angle is 90 degrees. Since AB and AC are two sides of the square, we can find the length of the sides using the distance formula.
- The distance between A(0, 0) and B(-3, 0) is √((-3 - 0)² + (0 - 0)²) = √9 = 3 units.
- The distance between A(0, 0) and C(0, 3) is √((0 - 0)² + (3 - 0)²) = √9 = 3 units.
Since AB and AC are equal and perpendicular, the fourth vertex of the square will be the same distance from point B and point C. This means it will be 3 units to the left of point C(0, 3) and 3 units below point B(-3, 0).
Therefore, the co-ordinates of the fourth vertex will be D(-3, 0).
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If the co-ordinates of three vertices of a square are A(0, 0), B(-3,0) and C(0,3), then the co-ordinates of its fourth vertex is?
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