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The efficiencies of A, B and C are in the ratio of 5 : 3 : 2. Working together, they can complete a task in 21 hours. In how many hours will B alone complete 40% of that task?    (SSC CGL-2018)
  • a)
    28
  • b)
    24
  • c)
    35
  • d)
    21
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
The efficiencies of A, B and C are in the ratio of 5 : 3 : 2. Working ...
work done by A, B and C in one day

x = 10 x 21
Time required to complete 40% work
Free Test
Community Answer
The efficiencies of A, B and C are in the ratio of 5 : 3 : 2. Working ...
Given Data:
Efficiencies of A, B, and C are in the ratio of 5:3:2
They can complete a task together in 21 hours

Calculating Individual Efficiencies:
Let the efficiencies of A, B, and C be 5x, 3x, and 2x respectively
Their combined efficiency = 5x + 3x + 2x = 10x
Given that they can complete the task in 21 hours, their combined efficiency = 1 task / 21 hours = 1/21
10x = 1/21
x = 1/210
Efficiency of B = 3x = 3 * (1/210) = 1/70

Calculating Time taken by B to complete 40% of the task:
Let the total task be T
40% of the task = 0.4 * T
Efficiency of B = 1/70
Time taken by B to complete 40% of the task = (0.4 * T) / (1/70) = 28 hours
Therefore, B alone will complete 40% of the task in 28 hours, which is option A.
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The efficiencies of A, B and C are in the ratio of 5 : 3 : 2. Working together, they can complete a task in 21 hours. In how many hours will B alone complete 40% of that task? (SSC CGL-2018)a)28b)24c)35d)21Correct answer is option 'A'. Can you explain this answer?
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