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A got 30% of the maximum marks in an examination and failed by 10 marks. However, B who took the same examination got 40% of the total marks and got 15 marks more than the passing marks. What were the passing marks in the examination?
- a)65
- b)75
- c)80
- d)None of these
Correct answer is option 'D'. Can you explain this answer?
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Most Upvoted Answer
A got30%of the maximum marks in an examination and failed by 10 marks....
(30/100)*T = P -10
(40/100)*T = P + 15
U will get P = 85
(40/100)*T = P + 15
U will get P = 85
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Community Answer
A got30%of the maximum marks in an examination and failed by 10 marks....
Understanding the Problem
To find the passing marks in the examination, let's break down the information given for both A and B.
Details for A:
- A scored 30% of the maximum marks.
- A failed by 10 marks.
Let the maximum marks be denoted as \( M \). Therefore, A's score can be expressed as:
- A's score = \( 0.3M \)
The passing marks (P) can be defined as:
- \( P = A's score + 10 \)
- \( P = 0.3M + 10 \)
Details for B:
- B scored 40% of the maximum marks.
- B scored 15 marks more than the passing marks.
B's score can be expressed as:
- B's score = \( 0.4M \)
According to the information given:
- \( 0.4M = P + 15 \)
Setting Up the Equations:
From the two equations we derived:
1. \( P = 0.3M + 10 \)
2. \( 0.4M = P + 15 \)
Substituting the expression for P from the first equation into the second:
- \( 0.4M = (0.3M + 10) + 15 \)
This simplifies to:
- \( 0.4M = 0.3M + 25 \)
Now, subtract \( 0.3M \) from both sides:
- \( 0.1M = 25 \)
Solving for \( M \):
- \( M = 250 \)
Calculating Passing Marks:
Now, substituting \( M \) back into the equation for P:
- \( P = 0.3 \times 250 + 10 \)
- \( P = 75 + 10 \)
- \( P = 85 \)
Since 85 is not listed among the options provided, the correct answer is option 'D': None of these.
To find the passing marks in the examination, let's break down the information given for both A and B.
Details for A:
- A scored 30% of the maximum marks.
- A failed by 10 marks.
Let the maximum marks be denoted as \( M \). Therefore, A's score can be expressed as:
- A's score = \( 0.3M \)
The passing marks (P) can be defined as:
- \( P = A's score + 10 \)
- \( P = 0.3M + 10 \)
Details for B:
- B scored 40% of the maximum marks.
- B scored 15 marks more than the passing marks.
B's score can be expressed as:
- B's score = \( 0.4M \)
According to the information given:
- \( 0.4M = P + 15 \)
Setting Up the Equations:
From the two equations we derived:
1. \( P = 0.3M + 10 \)
2. \( 0.4M = P + 15 \)
Substituting the expression for P from the first equation into the second:
- \( 0.4M = (0.3M + 10) + 15 \)
This simplifies to:
- \( 0.4M = 0.3M + 25 \)
Now, subtract \( 0.3M \) from both sides:
- \( 0.1M = 25 \)
Solving for \( M \):
- \( M = 250 \)
Calculating Passing Marks:
Now, substituting \( M \) back into the equation for P:
- \( P = 0.3 \times 250 + 10 \)
- \( P = 75 + 10 \)
- \( P = 85 \)
Since 85 is not listed among the options provided, the correct answer is option 'D': None of these.
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