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If an truck covers a distance of 400 m in 20 sec by accelerating uniformly find it acceleration and force acting upon it if truck weight 7 metric tons?
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If an truck covers a distance of 400 m in 20 sec by accelerating unifo...
Calculating Acceleration and Force of a Truck
Given data:
- Distance covered by the truck, d = 400 m
- Time taken to cover the distance, t = 20 sec
- Initial velocity, u = 0 m/s
- Final velocity, v = ?
- Acceleration, a = ?
- Weight of the truck, W = 7 metric tons = 7000 kg
- Force acting upon the truck, F = ?
Calculating Acceleration:
- Using the equation of motion: \(v = u + at\), where v is the final velocity
- \(v = 0 + a \times 20\)
- \(v = 20a\)
- Also, using the equation of motion: \(s = ut + \frac{1}{2}at^2\), where s is the distance covered
- \(400 = 0 \times 20 + \frac{1}{2}a \times 20^2\)
- \(400 = 200a\)
- \(a = \frac{400}{200}\)
- \(a = 2 \, m/s^2\)
Calculating Force:
- Force is given by Newton's second law of motion: \(F = ma\), where m is the mass of the object
- \(F = 7000 \times 2\)
- \(F = 14000 \, N\)
Conclusion:
- The acceleration of the truck is 2 m/s^2 and the force acting upon it is 14000 N. These values are calculated based on the distance covered and the weight of the truck.
Given data:
- Distance covered by the truck, d = 400 m
- Time taken to cover the distance, t = 20 sec
- Initial velocity, u = 0 m/s
- Final velocity, v = ?
- Acceleration, a = ?
- Weight of the truck, W = 7 metric tons = 7000 kg
- Force acting upon the truck, F = ?
Calculating Acceleration:
- Using the equation of motion: \(v = u + at\), where v is the final velocity
- \(v = 0 + a \times 20\)
- \(v = 20a\)
- Also, using the equation of motion: \(s = ut + \frac{1}{2}at^2\), where s is the distance covered
- \(400 = 0 \times 20 + \frac{1}{2}a \times 20^2\)
- \(400 = 200a\)
- \(a = \frac{400}{200}\)
- \(a = 2 \, m/s^2\)
Calculating Force:
- Force is given by Newton's second law of motion: \(F = ma\), where m is the mass of the object
- \(F = 7000 \times 2\)
- \(F = 14000 \, N\)
Conclusion:
- The acceleration of the truck is 2 m/s^2 and the force acting upon it is 14000 N. These values are calculated based on the distance covered and the weight of the truck.
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If an truck covers a distance of 400 m in 20 sec by accelerating uniformly find it acceleration and force acting upon it if truck weight 7 metric tons?
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If an truck covers a distance of 400 m in 20 sec by accelerating uniformly find it acceleration and force acting upon it if truck weight 7 metric tons? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about If an truck covers a distance of 400 m in 20 sec by accelerating uniformly find it acceleration and force acting upon it if truck weight 7 metric tons? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If an truck covers a distance of 400 m in 20 sec by accelerating uniformly find it acceleration and force acting upon it if truck weight 7 metric tons?.
If an truck covers a distance of 400 m in 20 sec by accelerating uniformly find it acceleration and force acting upon it if truck weight 7 metric tons? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about If an truck covers a distance of 400 m in 20 sec by accelerating uniformly find it acceleration and force acting upon it if truck weight 7 metric tons? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If an truck covers a distance of 400 m in 20 sec by accelerating uniformly find it acceleration and force acting upon it if truck weight 7 metric tons?.
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