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A race scooter is seen accelerating uniformly from 18.5m\s to 46.1m\s in 2.47 sec. Determine acceleration and distance travelled?
Verified Answer
A race scooter is seen accelerating uniformly from 18.5m\s to 46.1m\s ...
Acceleration = 46.1-18.5/2.47 = 11.47 m/s^2 and s = (46.1+18.5) 2.47 / 2 = 79.78 m
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Most Upvoted Answer
A race scooter is seen accelerating uniformly from 18.5m\s to 46.1m\s ...
Given data:
Initial velocity (u) = 18.5 m/s
Final velocity (v) = 46.1 m/s
Time taken (t) = 2.47 s

Acceleration (a):
Acceleration is the rate of change of velocity with respect to time. It can be calculated using the formula:
a = (v - u) / t

Substituting the given values:
a = (46.1 - 18.5) / 2.47
a = 27.6 / 2.47
a ≈ 11.18 m/s²

Therefore, the acceleration of the race scooter is approximately 11.18 m/s².

Distance travelled (s):
Distance can be calculated using the formula:
s = ut + (1/2)at²

Substituting the given values:
s = 18.5 * 2.47 + (1/2) * 11.18 * (2.47)²
s = 45.615 + (1/2) * 11.18 * 6.1009
s = 45.615 + 34.3875
s ≈ 79.0025 m

Therefore, the distance travelled by the race scooter is approximately 79.0025 meters.

Explanation:
- Acceleration is the rate at which the velocity of an object changes with time. It can be calculated by finding the difference between the final velocity and initial velocity, and dividing it by the time taken.
- In this case, the race scooter is seen accelerating uniformly, which means its acceleration remains constant throughout the given time interval.
- The acceleration is calculated to be approximately 11.18 m/s².
- Distance travelled can be calculated using the formula s = ut + (1/2)at², where u is the initial velocity, t is the time taken, and a is the acceleration.
- By substituting the given values into the formula, the distance travelled by the race scooter is calculated to be approximately 79.0025 meters.
- It is important to note that the given values and the calculated values are approximate due to rounding off the decimal places.
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A race scooter is seen accelerating uniformly from 18.5m\s to 46.1m\s in 2.47 sec. Determine acceleration and distance travelled?
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A race scooter is seen accelerating uniformly from 18.5m\s to 46.1m\s in 2.47 sec. Determine acceleration and distance travelled? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about A race scooter is seen accelerating uniformly from 18.5m\s to 46.1m\s in 2.47 sec. Determine acceleration and distance travelled? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A race scooter is seen accelerating uniformly from 18.5m\s to 46.1m\s in 2.47 sec. Determine acceleration and distance travelled?.
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