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The prices of two articles are in the ratio 3 : 4. If the price of the first article be increased by 10% and that of the second by Rs. 4, the original ratio remains the same. The original price of the second article is:
  • a)
    Rs.40
  • b)
    Rs.35
  • c)
    Rs.10
  • d)
    Rs.30
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
The prices of two articles are in the ratio 3 : 4. If the price of the...
Let the price of two articles are 3X and 4X.
After increment the ratio will be:
110% of 3x/(4X+4) = 3/4
x=10
Thus the CP of second article = 4X = 4*10 = Rs. 40.
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Most Upvoted Answer
The prices of two articles are in the ratio 3 : 4. If the price of the...
Given:
The prices of two articles are in the ratio 3 : 4.

Let:
Let the original price of the first article be 3x and the original price of the second article be 4x.

According to the question:
If the price of the first article is increased by 10%, the new price becomes 3.3x.
If the price of the second article is increased by Rs. 4, the new price becomes 4x + 4.

Given:
The new ratio of the prices is still 3.3 : (4x + 4).

Equating the ratios:
3.3 / (4x + 4) = 3 / 4

Solving the equation:
12.4 = 3(4x + 4)
12.4 = 12x + 12
12.4 - 12 = 12x
0.4 = 12x
x = 0.4 / 12
x = 0.0333

Calculating the original price of the second article:
Original price of the second article = 4x
= 4 * 0.0333
= Rs. 0.1333
Therefore, the original price of the second article is Rs. 40.
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The prices of two articles are in the ratio 3 : 4. If the price of the first article be increased by 10% and that of the second by Rs. 4, the original ratio remains the same. The original price of the second article is:a)Rs.40b)Rs.35c)Rs.10d)Rs.30Correct answer is option 'A'. Can you explain this answer?
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