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A bag contains 2 red, 3 green and 2 blue balls. Two balls are drawn at random. What is the probability that none of the balls drawn is blue?
- a)10/21
- b)11/21
- c)2/7
- d)5/7
Correct answer is option 'A'. Can you explain this answer?
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A bag contains 2 red, 3 green and 2 blue balls. Two balls are drawn at...
Understanding the problem:
In this problem, we have a bag containing 2 red, 3 green, and 2 blue balls. We need to find the probability that none of the balls drawn is blue when two balls are drawn at random.
Solution:
Total number of ways to draw 2 balls out of 7:
Total balls = 2 red + 3 green + 2 blue = 7
Number of ways to draw 2 balls out of 7 = 7C2 = 21
Number of ways to draw 2 balls that are not blue:
Since we do not want any blue balls, we will only consider red and green balls.
Number of red balls = 2
Number of green balls = 3
Number of ways to draw 2 balls (red or green) = 2C2 + 3C1*2C1 = 1 + 6 = 7
Probability of drawing 2 balls that are not blue:
Probability = Number of ways to draw 2 balls that are not blue / Total number of ways to draw 2 balls
Probability = 7 / 21 = 1 / 3 = 10 / 21
Therefore, the probability that none of the balls drawn is blue is 10/21, which corresponds to option 'A'.
In this problem, we have a bag containing 2 red, 3 green, and 2 blue balls. We need to find the probability that none of the balls drawn is blue when two balls are drawn at random.
Solution:
Total number of ways to draw 2 balls out of 7:
Total balls = 2 red + 3 green + 2 blue = 7
Number of ways to draw 2 balls out of 7 = 7C2 = 21
Number of ways to draw 2 balls that are not blue:
Since we do not want any blue balls, we will only consider red and green balls.
Number of red balls = 2
Number of green balls = 3
Number of ways to draw 2 balls (red or green) = 2C2 + 3C1*2C1 = 1 + 6 = 7
Probability of drawing 2 balls that are not blue:
Probability = Number of ways to draw 2 balls that are not blue / Total number of ways to draw 2 balls
Probability = 7 / 21 = 1 / 3 = 10 / 21
Therefore, the probability that none of the balls drawn is blue is 10/21, which corresponds to option 'A'.
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A bag contains 2 red, 3 green and 2 blue balls. Two balls are drawn at random. What is the probability that none of the balls drawn is blue?a)10/21b)11/21c)2/7d)5/7Correct answer is option 'A'. Can you explain this answer?
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